Mathematics - Functions

Hello,
Very stuck on this sort of question. For inverse functions, some of them aren't functions when they are inversed, so the domain must be restricted, or atleast thats what I understood from my lesson. but, I'm very stuck on which side to choose. It's hard to explain, but I'll leave question 3bi in the desc.

Reply 1

Anonymous #2

Depends on whether the new function is a rational function or even a Logarithmic function.

Basically, when rearranging, the inverse function is not one to one, so the domain needs to be restricted, before or after the tp of the og function or smt similar, but I don't know which restriction to choose

Reply 4

Anonymous #3

Original post by Anonymous

Each x value can have only one y value, so draw out the graph and spot your domain

Reply 5

Anonymous #1

Original post by Anonymous

Each x value can have only one y value, so draw out the graph and spot your domain

Sorry I'm a bit confused on what you mean by this

Reply 6

Anonymous #3

Original post by Anonymous

Sorry I'm a bit confused on what you mean by this

If you look at the graph of root x, with no domain, you can see at every x coordinate there are 2 y coordinates. Therefore not a function

Reply 7

Anonymous #4

I'm not sure if you are famillar with a function output diagram that helped me understand, but basically a function can only have 1 output from its input, by that logic if you inverse and get a equation and you get 2 potential answers it is no longer a function but if you change the domains/ ranges then you can have a graph with the new inverse equation and is a function as it should have only 1 output
hope this helps

Reply 8

Anonymous #4

Original post by Anonymous

you chose it from the largest section of the graph that doesn't repeat so f(x) doesn't have the same value.
can be one to one or many x values to one y value graph types