QUESTION:

A system is described by the following three equations:

aB=cd

MF-a=Mx

x=Bd

Express x in the form x= F/A

where A is a function of c , B and M in its simplest form.

I rearranged third equation to get d=x/B

Then put that into first equation so aB=cx/B so a=cx/B^2

Then I put this into the second equation so: MF-cx/B^2 so MF=x(M-c/B^2) which gives x=MF/M-c/B^2 which gives x=MB^2F/MB^2-c which is wrong.

Please help.

A system is described by the following three equations:

aB=cd

MF-a=Mx

x=Bd

Express x in the form x= F/A

where A is a function of c , B and M in its simplest form.

I rearranged third equation to get d=x/B

Then put that into first equation so aB=cx/B so a=cx/B^2

Then I put this into the second equation so: MF-cx/B^2 so MF=x(M-c/B^2) which gives x=MF/M-c/B^2 which gives x=MB^2F/MB^2-c which is wrong.

Please help.

Original post by Skye10HH

QUESTION:

A system is described by the following three equations:

aB=cd

MF-a=Mx

x=Bd

Express x in the form x= F/A

where A is a function of c , B and M in its simplest form.

I rearranged third equation to get d=x/B

Then put that into first equation so aB=cx/B so a=cx/B^2

Then I put this into the second equation so: MF-cx/B^2 so MF=x(M-c/B^2) which gives x=MF/M-c/B^2 which gives x=MB^2F/MB^2-c which is wrong.

Please help.

A system is described by the following three equations:

aB=cd

MF-a=Mx

x=Bd

Express x in the form x= F/A

where A is a function of c , B and M in its simplest form.

I rearranged third equation to get d=x/B

Then put that into first equation so aB=cx/B so a=cx/B^2

Then I put this into the second equation so: MF-cx/B^2 so MF=x(M-c/B^2) which gives x=MF/M-c/B^2 which gives x=MB^2F/MB^2-c which is wrong.

Please help.

Not checked, but you need just F on the numerator, so divide both numerator and denominator by MB^2 and you get ...

Original post by mqb2766

Not checked, but you need just F on the numerator, so divide both numerator and denominator by MB^2 and you get ...

MB^2 is not a factor of the denominator so I don’t think you can do that. Correct me if I’m wrong.

Original post by Skye10HH

MB^2 is not a factor of the denominator so I don’t think you can do that. Correct me if I’m wrong.

The desired expression on the denominator depends on M and B so

(MB^2 - c) / (MB^2) = ...

If you backed up your working a line where you had

MF = x(...)

then divide through by M to get

F = x (...)

then divide through by (...) to get

x = F/(...)

Original post by mqb2766

The desired expression on the denominator depends on M and B so

(MB^2 - c) / (MB^2) = ...

If you backed up your working a line where you had

MF = x(...)

then divide through by M to get

F = x (...)

then divide through by (...) to get

x = F/(...)

(MB^2 - c) / (MB^2) = ...

If you backed up your working a line where you had

MF = x(...)

then divide through by M to get

F = x (...)

then divide through by (...) to get

x = F/(...)

So now I did:

MF = x(M-C/B^2)

F = x(1-C/MB^2)

So x =F/(1-C/MB^2)

But this is still incorrect

Original post by Skye10HH

So now I did:

MF = x(M-C/B^2)

F = x(1-C/MB^2)

So x =F/(1-C/MB^2)

But this is still incorrect

MF = x(M-C/B^2)

F = x(1-C/MB^2)

So x =F/(1-C/MB^2)

But this is still incorrect

Edit - looks like you have a sign wrong when you take a term over

(edited 2 weeks ago)

Original post by mqb2766

Have you the isaac link / did you put

1 - c / (MB^2)

Edit - looks like you have a sign wrong when you take a term over

1 - c / (MB^2)

Edit - looks like you have a sign wrong when you take a term over

Got it now, thanks

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