Help with A Level Chemistry

Could someone help me with this question please:

13.80g of a solid monoprotic acid was dissolved in water and made up to 250.0cm^3. 25.00cm^3 portions of this were titrated against 0.2500mol dm^-3 sodium hydroxide, requiring 23.50cm^3. Calculate the Mr of the acid.

I did : calculate moles of NaOH (0.25 x 0.0235=0.005875)
then use that to get Mr of acid a(13.8/0.005875=2,349) but this seems super wrong!

Thanks!!

The moles of NaOH in 23.5 cm^3 is equal to the number of moles of HA in 25.0 cm^3 of the solution. Notice, however, that a total of 250 cm^3 of solution was prepared. This is something you have missed.
How might this affect your answer?

so would the answer be /10 so 234.9 to one d.p? thanks