In year 12 doing free radical substitutions rn, and I do not get propagation at all. These are the equations for propagation in the halogenation of methane: CH4 + Cl⬤ → CH3⬤ + HCl CH3⬤ + Cl2 → CH3Cl + Cl⬤ Why are there 2 reactions? Are they 2 different reactions going on at the same time or something? Why does the top equation only have 1 Cl radical? I honestly have no clue what is going on here lol
Havent done this for a while, but propagation is a radical reaction where there is one radical reactant and one radical product, both reactions will occur in the process of the reaction and they are both classed as propagation steps
Havent done this for a while, but propagation is a radical reaction where there is one radical reactant and one radical product, both reactions will occur in the process of the reaction and they are both classed as propagation steps
So would the CH4 + Cl⬤ → CH3⬤ + HCl reaction happen before the CH3⬤ + Cl2 → CH3Cl + Cl⬤ reaction?