Chemistry a level question
how do i solve this
25 cm³ of a 0.1 moldm³ solution of an acid H.A reacts with 75cm³ of a 0.1 moldm³ solution of NaOH What is the value of x?
Equation: HxA + NaOH → + NaxA + XH₂O
Answer X=3
25 cm³ of a 0.1 moldm³ solution of an acid H.A reacts with 75cm³ of a 0.1 moldm³ solution of NaOH What is the value of x?
Equation: HxA + NaOH → + NaxA + XH₂O
Answer X=3
Reply 1
Original post
by well-educated-amhow do i solve this
25 cm³ of a 0.1 moldm³ solution of an acid H.A reacts with 75cm³ of a 0.1 moldm³ solution of NaOH What is the value of x?
Equation: HxA + NaOH → + NaxA + XH₂O
Answer X=3
25 cm³ of a 0.1 moldm³ solution of an acid H.A reacts with 75cm³ of a 0.1 moldm³ solution of NaOH What is the value of x?
Equation: HxA + NaOH → + NaxA + XH₂O
Answer X=3
The rule of the house is that you have to try before we make any suggestions.
I am waiting with patience.
Reply 2
Original post
by well-educated-amhow do i solve this
25 cm³ of a 0.1 moldm³ solution of an acid H.A reacts with 75cm³ of a 0.1 moldm³ solution of NaOH What is the value of x?
Equation: HxA + NaOH → + NaxA + XH₂O
Answer X=3
25 cm³ of a 0.1 moldm³ solution of an acid H.A reacts with 75cm³ of a 0.1 moldm³ solution of NaOH What is the value of x?
Equation: HxA + NaOH → + NaxA + XH₂O
Answer X=3
Whenever you get these types of questions, it’s useful to start by calculating the number of moles of each substance, does that help you?
Reply 3
Original post
by anonymous56754Whenever you get these types of questions, it’s useful to start by calculating the number of moles of each substance, does that help you?
Yes, the right way to handle such problems.
Please let us know your attempt.
I'm here to help you practice. If you're sharing your work, I'll give you little hints to keep you going. If you're still stuck, I can give you more detailed help. Just let me know which part is confusing you.
EDIT:
1.
Calculate the moles of each reactant
2.
For the acid HxA
3.
For NaOH
4.
Analyze the stoichiometry of the reaction and find stoichiometric ratio between HxA and NaOH
5.
Set up the stoichiometric ratio to solve for x
Sandro
(edited 1 year ago)
Reply 4
This is a limiting reagent problem.
a) Find the mole of each reactant.
b) Determine the limiting reagent.
c) Apply the stoichiometry relationship.
a) Find the mole of each reactant.
b) Determine the limiting reagent.
c) Apply the stoichiometry relationship.
Reply 5
Original post
by awchemtutorThis is a limiting reagent problem.
a) Find the mole of each reactant.
b) Determine the limiting reagent.
c) Apply the stoichiometry relationship.
a) Find the mole of each reactant.
b) Determine the limiting reagent.
c) Apply the stoichiometry relationship.
Hello awchemtutor!
I apologise for this intrusion, but in my humble opinion the problem can be solved without identifying the limiting reagent.
The problem text does not ask you to identify the limiting reagent. Doesn't it?
Kind regards,
Sandro
Reply 6
20
Original post
by NitrotolueneHello awchemtutor!
I apologise for this intrusion, but in my humble opinion the problem can be solved without identifying the limiting reagent.
The problem text does not ask you to identify the limiting reagent. Doesn't it?
Kind regards,
Sandro
I apologise for this intrusion, but in my humble opinion the problem can be solved without identifying the limiting reagent.
The problem text does not ask you to identify the limiting reagent. Doesn't it?
Kind regards,
Sandro
It would have been better if the Q were clearer, e.g. 25 cm³ ... of H.A reacts "exactly" with...
But you're right, it isn't a limiting reagent Q. The only way you can solve the problem is to assume that neither is in excess.
Reply 7
Original post
by NitrotolueneHello awchemtutor!
I apologise for this intrusion, but in my humble opinion the problem can be solved without identifying the limiting reagent.
The problem text does not ask you to identify the limiting reagent. Doesn't it?
Kind regards,
Sandro
I apologise for this intrusion, but in my humble opinion the problem can be solved without identifying the limiting reagent.
The problem text does not ask you to identify the limiting reagent. Doesn't it?
Kind regards,
Sandro
True. But it is a good idea for students to learn that if amounts are given for the reactants, to determine the limiting reagent. Just in case, equation is not a 1:1 ratio.
I agree in this case, it is straight forward and the limiting reagent is clear to see.
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