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Chemistry amount of substance question

Can anyone help with this question about titration?

A 25.0 cm3 sample of vinegar was diluted in a 250 cm3 volumetric flask. This was then put in a burette and 23.10 cm3 of the diluted vinegar neutralised 25.0 cm3 of
0.100 mol dm-3 NaOH. Calculate the concentration of the vinegar in g dm-3.

CH3.CO2.H + NaOH CH3.CO2.Na^+ + H20


thanks
... and your ideas are?
Original post by Dain00000
Can anyone help with this question about titration?

A 25.0 cm3 sample of vinegar was diluted in a 250 cm3 volumetric flask. This was then put in a burette and 23.10 cm3 of the diluted vinegar neutralised 25.0 cm3 of
0.100 mol dm-3 NaOH. Calculate the concentration of the vinegar in g dm-3.

CH3.CO2.H + NaOH CH3.CO2.Na^+ + H20


thanks


Similarly to how Charro responded to one of your other threads, look for information you can use - perhaps the volume and concentration of NaOH may be a good starting point.
Original post by Dain00000
Can anyone help with this question about titration?
A 25.0 cm3 sample of vinegar was diluted in a 250 cm3 volumetric flask. This was then put in a burette and 23.10 cm3 of the diluted vinegar neutralised 25.0 cm3 of
0.100 mol dm-3 NaOH. Calculate the concentration of the vinegar in g dm-3.
CH3.CO2.H + NaOH CH3.CO2.Na^+ + H20
thanks


Are you serious?
Reply 4
Original post by TypicalNerd
Similarly to how Charro responded to one of your other threads, look for information you can use - perhaps the volume and concentration of NaOH may be a good starting point.


Never mind guys I got the hang of back titrations!!! Should probably say on the other 2 posts too
Original post by Dain00000
Never mind guys I got the hang of back titrations!!! Should probably say on the other 2 posts too

This particular question isn’t a back titration. It’s a standard acid-base titration that involves accounting for a dilution.

It’s great to hear you are finding titrations more manageable. If you have any further chemistry questions, feel free to ask them on TSR and I’m sure you can either be guided through the problems or be given pointers as to what things to look up to help improve your understanding.
Reply 6
Original post by TypicalNerd
This particular question isn’t a back titration. It’s a standard acid-base titration that involves accounting for a dilution.
It’s great to hear you are finding titrations more manageable. If you have any further chemistry questions, feel free to ask them on TSR and I’m sure you can either be guided through the problems or be given pointers as to what things to look up to help improve your understanding.


Really? I watched chemistry tutor on YouTube and I applied his method of diagrams to this question and it helped
Original post by Dain00000
Really? I watched chemistry tutor on YouTube and I applied his method of diagrams to this question and it helped

By definition, a back titration is carried out by reacting the unknown amount of substance A with an excess of some other reagent B (which you either know the number of moles of or can calculate the number of moles of quite easily) and then titrating what’s left of this other reagent B to work out how much is left and therefore how much of the substance A reacted with that other reagent B.

There is a strategy for back titrations, which essentially starts off by doing a titration calculation as normal, but then doing a limiting reagent calculation.
Reply 8
Original post by TypicalNerd
By definition, a back titration is carried out by reacting the unknown amount of substance A with an excess of some other reagent B (which you either know the number of moles of or can calculate the number of moles of quite easily) and then titrating what’s left of this other reagent B to work out how much is left and therefore how much of the substance A reacted with that other reagent B.
There is a strategy for back titrations, which essentially starts off by doing a titration calculation as normal, but then doing a limiting reagent calculation.


Oh yeah I’m familiar with that.
This is gonna be such a long year of chemistry 😖
Original post by Dain00000
Oh yeah I’m familiar with that.
This is gonna be such a long year of chemistry 😖

Hello Dain00000!
Another way to define the "back titration" for posterity:

" If the reaction is not fast enough or the end point of the reaction is not easy to detect, a quantitative chemical analysis called "back titration" is used. This consists of adding a known amount of titrant to the sample, well in excess of that required to complete the reaction.
The sample reacts by partially consuming the added titrant. The excess titrant is then in turn titrated with a second titrant of known concentration with which the first titrant reacts quickly and easily."

Bye,
The flag of Italy.png
Sandro
(edited 1 month ago)
Reply 10
Original post by Nitrotoluene
Hello Dain00000!
Another way to define the "back titration" for posterity:
" If the reaction is not fast enough or the end point of the reaction is not easy to detect, a quantitative chemical analysis called "back titration" is used. This consists of adding a known amount of titrant to the sample, well in excess of that required to complete the reaction.
The sample reacts by partially consuming the added titrant. The excess titrant is then in turn titrated with a second titrant of known concentration with which the first titrant reacts quickly and easily."
Bye,
The flag of Italy.png
Sandro


Good to know Sandro thanks

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