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Chemistry amount of substance question

Can anyone help with this question about titration?

An unknown metal carbonate reacts with hydrochloric acid according to the following equation.
M2.CO3(aq) + 2 HCl(aq) 2 MCl(aq) + CO2(g) + H20(L)
A 3.96 g sample of M2CO3 was dissolved in distilled water to make 250 cm3 of solution. A 25.0 cm3 portion of this solution required 32.8 cm3 of 0.175 mol dm-3 hydrochloric acid for complete reaction. Calculate the Mr of M2CO3 and identify the metal M


Thanks
Original post by Dain00000
Can anyone help with this question about titration?
An unknown metal carbonate reacts with hydrochloric acid according to the following equation.
M2.CO3(aq) + 2 HCl(aq) 2 MCl(aq) + CO2(g) + H20(L)
A 3.96 g sample of M2CO3 was dissolved in distilled water to make 250 cm3 of solution. A 25.0 cm3 portion of this solution required 32.8 cm3 of 0.175 mol dm-3 hydrochloric acid for complete reaction. Calculate the Mr of M2CO3 and identify the metal M
Thanks

... and your ideas are?
Reply 2
Original post by charco
... and your ideas are?


Pardon?
Original post by Dain00000
Pardon?

How do you think that you should start off?
Reply 4
Original post by charco
How do you think that you should start off?


Well this question is from chem revise and he does give you the solution and answer to it and yes I understand the beginning where he just calculates the mole but after that (especially the end part) I don’t get at all. So right now I could either just lie and give you the Chemrevise answer pretending like I understand what I’m doing or I can honestly say I have no clue
Original post by Dain00000
Well this question is from chem revise and he does give you the solution and answer to it and yes I understand the beginning where he just calculates the mole but after that (especially the end part) I don’t get at all. So right now I could either just lie and give you the Chemrevise answer pretending like I understand what I’m doing or I can honestly say I have no clue

Start by unpacking the question to see what you CAN find out.

A 3.96 g sample of M2CO3 was dissolved in distilled water to make 250 cm3 of solution. A 25.0 cm3 portion of this solution required 32.8 cm3 of 0.175 mol dm-3 hydrochloric acid for complete reaction. Calculate the Mr of M2CO3 and identify the metal M.

The part in bold allows you to calculate the mol of HCl
Reply 6
I think the problem with me is having no clue where to begin with these complicated questions 😅 So we do 32.8/1000=0.0328 and then moles=conc x vol so 0.175 x 0.0328 =0.00574 moles of HCl? I’m presuming we do something with the 1:2 ratio? So 0.00574/2=0.00287 moles of M2.CO3?
Original post by Dain00000
Can anyone help with this question about titration?

An unknown metal carbonate reacts with hydrochloric acid according to the following equation.
M2.CO3(aq) + 2 HCl(aq) 2 MCl(aq) + CO2(g) + H20(L)
A 3.96 g sample of M2CO3 was dissolved in distilled water to make 250 cm3 of solution. A 25.0 cm3 portion of this solution required 32.8 cm3 of 0.175 mol dm-3 hydrochloric acid for complete reaction. Calculate the Mr of M2CO3 and identify the metal M


Thanks

You are correct so far. Now you need to pay close attention to the volume of solution used and the volume of solution made so you can know how much M2CO3 was actually reacted.

Remember the equation moles = mass/Mr?

Might it be possible to apply it in this case?
(edited 2 months ago)
Reply 8
Found a method of thinking that works for me so nvm!!

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