The Student Room Group

Bmo 2024

How did everyone do? I did five questions (1-5) but sillied geometry, so thats about 4 questions right. Any predictions for merit, distinction, and medal awards this year?

Reply 1

I'm hoping that the score boundary is lower - I completely didn't understand Q6 and I messed up the geometry. IMO it's difficulty is slightly harder than BMO 2021, so it'll probably be around there

Reply 2

I was really ill on the day which is really irritating, I don't think I would've done miles better or anything but it would've been nice to be at my best yknow. I managed 1, 2 and 5, and am annoyed I didn't do 3 cause I know the solution now after thinking about it for a bit. The geometry one was a bit evil, and q6 was definitely a tough one as per usual. That's my opinions lol. I reckon it'll be lower boundaries than last year, maybe 35-40 for BMO2? At a guess...

Reply 3

Original post
by chris8topheryu
How did everyone do? I did five questions (1-5) but sillied geometry, so thats about 4 questions right. Any predictions for merit, distinction, and medal awards this year?

I think it was an easy paper, Q6 I found way too easy; it was just pigeonhole principle I think...
Q4 (Geometry) was horrible though

Reply 4

Original post
by MaxM360
I think it was an easy paper, Q6 I found way too easy; it was just pigeonhole principle I think...
Q4 (Geometry) was horrible though


How did you solve Q6 using just the pigeonhole principle?

Reply 5

Original post
by JeffDaPenguin
How did you solve Q6 using just the pigeonhole principle?

Not worked it through/seen the solution, but Id imagine you could consider how many are one unit away (squared distance, so share a face) two units away (share an edge) three units away (share a vertex) etc up to 27 units away (max squared distance), and argue pigeonhole from those numbers. Though you might have to be careful about assuming unit cubes are different colours in the arguments for different distances.

Id guess working it with a 4*4 2d grid (or even smaller) might give the basic insight.
(edited 11 months ago)

Reply 6

Original post
by MaxM360
I think it was an easy paper, Q6 I found way too easy; it was just pigeonhole principle I think...
Q4 (Geometry) was horrible though

I'm surprised a lot of people are finding Q4 difficult, personally I didn't have too much issues. I didn't get Q6 though like you, tbh I didn't even spend any time on it bc i just assumed my time would be better spent working on Q5 (for which I got an (almost) full solution I think)

Reply 7

Original post
by rstather
I'm surprised a lot of people are finding Q4 difficult, personally I didn't have too much issues. I didn't get Q6 though like you, tbh I didn't even spend any time on it bc i just assumed my time would be better spent working on Q5 (for which I got an (almost) full solution I think)

Honestly Q4 isn't that difficult, I just had trouble thinking about it at the time. I also thought Q5 was really easy but that's just my opinion.

Reply 8

Original post
by mqb2766
Not worked it through/seen the solution, but Id imagine you could consider how many are one unit away (squared distance, so share a face) two units away (share an edge) three units away (share a vertex) etc up to 27 units away (max squared distance), and argue pigeonhole from those numbers. Though you might have to be careful about assuming unit cubes are different colours in the arguments for different distances.
Id guess working it with a 4*4 2d grid (or even smaller) might give the basic insight.


I can’t see how that would work

Reply 9

Original post
by JeffDaPenguin
I can’t see how that would work

16 possible distances.
Pigeonhole shows there must be at least 22 of one type.
22 = 16a+b
B = 6.
Pigeonhole shows there must be 6 pairs

Reply 10

Original post
by MaxM360
16 possible distances.
Pigeonhole shows there must be at least 22 of one type.
22 = 16a+b
B = 6.
Pigeonhole shows there must be 6 pairs


I agree that there are at least 22 cubes of one type, where does 16 come from? And where does 22 = 16a + b come from?

Reply 11

Original post
by JeffDaPenguin
I agree that there are at least 22 cubes of one type, where does 16 come from? And where does 22 = 16a + b come from?

16a + b is adapted pigeonhole
When you calculate all possible distances; there are 16

Reply 12

Has anyone received the invitation for the Hungary camp this year?

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