The Student Room Group

Maths question ln

Hi, I was trying to simplify this but I’m getting the wrong answer. I’m not sure where I have gone wrong though, please could someone check it? I have attached my working below.
https://ibb.co/JsGRSzF
Thanks!

Reply 1

Original post
by anonymous56754
Hi, I was trying to simplify this but I’m getting the wrong answer. I’m not sure where I have gone wrong though, please could someone check it? I have attached my working below.
https://ibb.co/JsGRSzF
Thanks!

It would help to see the original question and your writing isnt the clearest, but near the bottom sqrt(k) seems to become k (both times) on the penultimate line?

Reply 2

Original post
by mqb2766
It would help to see the original question and your writing isnt the clearest, but near the bottom sqrt(k) seems to become k (both times) on the penultimate line?

Sorry, here is the question, mark scheme and my attempt, hopefully it’s clearer. IMG_0687.jpeg
IMG_0689.jpeg
IMG_0690.jpeg

Reply 3

The first part of the question is a specific value of k (-3) and is meant to get you thinking about the derivative etc. For that value, the gradient is always > 0, so increasing, which it obviously isnt in (ii) so they want you to think about what values of k might correspond to a function which has a minimum (zero gradient) and has "u" shape and whats the range of g()

So if you differentiate the g(x), can you find the values of x which correspond to a minimum. Assuming you have the minimum when e^(4x) = k or e^(2x) = sqrt(k), you can sub that into g() and pretty much write down gmin, rather than going through your working and its 2sqrt(k) as mentioned in the previous post.

But its less about an algebra slog and more about thinking what you need to do and as its only 5 marks, there shouldnt really be an algebra slog in the first place.

Reply 4

Original post
by mqb2766
The first part of the question is a specific value of k (-3) and is meant to get you thinking about the derivative etc. For that value, the gradient is always > 0, so increasing, which it obviously isnt in (ii) so they want you to think about what values of k might correspond to a function which has a minimum (zero gradient) and has "u" shape and whats the range of g()
So if you differentiate the g(x), can you find the values of x which correspond to a minimum. Assuming you have the minimum when e^(4x) = k or e^(2x) = sqrt(k), you can sub that into g() and pretty much write down gmin, rather than going through your working and its 2sqrt(k) as mentioned in the previous post.
But its less about an algebra slog and more about thinking what you need to do and as its only 5 marks, there shouldnt really be an algebra slog in the first place.
Thank you, I tried your method and it works! But, I'm still unsure where my algebra has gone wrong in the previous post, it may be useful for future questions.

Reply 5

Original post
by anonymous56754
Thank you, I tried your method and it works! But, I'm still unsure where my algebra has gone wrong in the previous post, it may be useful for future questions.

You have
g(x) = sqrt(k) + k / sqrt(k)
Really the left hand side isnt a function of x any more (it kind of shows youre not sure what youre calculating, so gmin(k)) but you seem to multiply the right hand side only by sqrt(k) to get 2k. However its an equation and you have to maintain balance so if you multiplied the right by sqrt(k) youd have to do the same to the left to get
g(x)*sqrt(k) = 2k
which is the same as g(x) = 2sqrt(k).

I guess youre not treating it as an equation and the "= " literally means that both lines are the same length or both sides balance / same value. You cant make one line longer arbitrarily.
(edited 1 year ago)

Reply 6

Original post
by mqb2766
You have
g(x) = sqrt(k) + k / sqrt(k)
Really the left hand side isnt a function of x any more (it kind of shows youre not sure what youre calculating, so gmin(k)) but you seem to multiply the right hand side only by sqrt(k) to get 2k. However its an equation and you have to maintain balance so if you multiplied the right by sqrt(k) youd have to do the same to the left to get
g(x)*sqrt(k) = 2k
which is the same as g(x) = 2sqrt(k).
I guess youre not treating it as an equation and the "= " literally means that both lines are the same length or both sides balance / same value. You cant make one line longer arbitrarily.

oh, i see where i went wrong, thank you so much 🙂

Reply 7

Original post
by anonymous56754
oh, i see where i went wrong, thank you so much 🙂

If youve a bit of spare time (1/2 hr?), it may help to think about the functions
x + 1/x
and
x + k/x
as both of these are famous simple but slightly complex functions which are essentially gcse.

The function g(x) here is also has an exponential transformation of x, but otherwise its very similar. So maybe sketch (plot in desmos) the functions, think how theyre similar / different etc. Rather than treating it as an algebra exercise, think about the simple properties of each term and how they combine.

Quick Reply

How The Student Room is moderated

To keep The Student Room safe for everyone, we moderate posts that are added to the site.