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Physics a level question resolving forces

Hey could someone please explain how they found r, specifically how they resolved that 1.8m section because I can’t see it
IMG_0031.jpeg
(edited 2 months ago)
Reply 1
What is the question that this answer is from.
Original post by Nat4695
Hey could someone please explain how they found r, specifically how they resolved that 1.8m section because I can’t see it
IMG_0031.jpeg



The answer resolves the length of 1.8 m using a right-angled triangle where the length 1.8 m is the hypotenuse side.

Say we draw a right-angled triangle on the right string where the string is the hypotenuse side, the string makes an angle θ (given as 1.5° in the answer) with the vertical dotted line (this vertical line is extended downward and is the adjacent side of the right-angled triangle) and at the bottom of the extended vertical dotted line, we draw a horizontal line connected to the bottom of the string (this horizontal line is the opposite side of angle θ). This forms the right-angled triangle.

The separation r is the sum of 0.5 m and the 2 horizontal sections of the right-angled triangles for the left and right strings.

We can find the horizontal section using the sine ratio in a right-angled triangle.

Spoiler

Reply 3
Original post by Eimmanuel
The answer resolves the length of 1.8 m using a right-angled triangle where the length 1.8 m is the hypotenuse side.
Say we draw a right-angled triangle on the right string where the string is the hypotenuse side, the string makes an angle θ (given as 1.5° in the answer) with the vertical dotted line (this vertical line is extended downward and is the adjacent side of the right-angled triangle) and at the bottom of the extended vertical dotted line, we draw a horizontal line connected to the bottom of the string (this horizontal line is the opposite side of angle θ). This forms the right-angled triangle.
The separation r is the sum of 0.5 m and the 2 horizontal sections of the right-angled triangles for the left and right strings.
We can find the horizontal section using the sine ratio in a right-angled triangle.

Spoiler


Thank you so much, i got it now :smile:

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