physics question thermodynamics

hi, please could I have help on the last part of this question? delta U is equal to -64 and since U=Q + W, I worked out Q= -64-76= -140J so surely thermal energy is transferred from the gas because Q is negative.
question: https://ibb.co/KDjYDyk
thanks!

You have applied the correct equation of 1st law of thermodynamics but "misinterpreted" work done by the gas is equal to work done on the gas.
When you quote ΔU = q + W, you need to know that you have implicitly assumed W is work done on the system which is work done on the gas for this question.
Work done on the gas = - work done by the gas

ohh ok so -64= q - 76 so q= 12?

Agreed that q = 12 J.