Do we have to integrate ∫x dy, not really clear on the spec. Help would be great thanks
Your question isn't really clear. Is x supposed to be a function of y in that expression?
What you call the variable of integration isn't important - you could define u as a function of t and integrate u(t) dt, and so on! The "spec" shouldn't need to tell you that
Your question isn't really clear. Is x supposed to be a function of y in that expression? What you call the variable of integration isn't important - you could define u as a function of t and integrate u(t) dt, and so on! The "spec" shouldn't need to tell you that
Your question isn't really clear. Is x supposed to be a function of y in that expression? What you call the variable of integration isn't important - you could define u as a function of t and integrate u(t) dt, and so on! The "spec" shouldn't need to tell you that
Ive done every question in the textbook and not once have I had a question that you had to consider the region as it your looking from the y-axis instead of the x-axis (If that makes sense)
Neglecting the parametric part, but you flip between Int y(x) dx and Int x(y) dy when you consider volumes of revolution about x or y axes for instance. It shouldnt be a big deal when you think of it simply as a riemann sum with either vertical or horizontal rectangles.
Neglecting the parametric part, but you flip between Int y(x) dx and Int x(y) dy when you consider volumes of revolution about x or y axes for instance. It shouldnt be a big deal when you think of it simply as a riemann sum with either vertical or horizontal rectangles.
I feel like you are my maths tutor at this point, dedication from you is crazy. I dont think volumes of revolutions are apart of my specification (I think it got moved to FM)
I feel like you are my maths tutor at this point, dedication from you is crazy. I dont think volumes of revolutions are apart of my specification (I think it got moved to FM)
Quite possibly for volumes of revolution, but its probably best to say its on the boundary of the spec, so you should be able to do it with a nudge, as its not really different from the usual integration set up as davros noted.
Quite possibly for volumes of revolution, but its probably best to say its on the boundary of the spec, so you should be able to do it with a nudge, as its not really different from the usual integration set up as davros noted.
Okay so Ill just make sure Im familiar with the process, thank you