The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

This discussion is now closed.

Check out other Related discussions

S2 - here we go again...

Hey - sorry to keep posting about S2... it'll be over soon so you need not worry about being
bombarded with questions beyond the end of the week!

Basically,

for a p.d.f.
f(x) = (1/9)(8-x) 5=< x < 8

now, when I integrate this:

(1/9) int (between 5 and x0) 8-x dx

I therefore get F(x) for this part of the f(x) to equal:

(1/10)(16x - x^2 - 55)

The book seems to think it is as above but with -46 instead of -55.

For those with the book "Revise for Stats 2" this question is taken from 7c) of the practice paaper
in the rear of the book.

Is the book wrong? Or is it me?

Hope someone can help.

Thanks

RG

Related discussions

Latest

Trending

Trending

Articles for you