Magnetic Fields - AQA Physics June 2023 - Paper 3 - Question doubt
Hi everyone,
I am in Year 13 studying AQA Physics for A Level, was doing the June 2023 papers and came across this question in Paper 3. The question is attached. I do not understand Q3.2, so have included both the context of the question (if needed) and the Q3.2 I do not understand how to do, and don't understand how the mark scheme has done it.
One thing I am confused about is that to find the horizontal component of Magnetic Flux Density, why have they taken the vertical component in the mark scheme which is BHcos45.
I would appreciate it if someone could try to solve this question 3.2 and explain to me how they did it, since I am very confused.
I am in Year 13 studying AQA Physics for A Level, was doing the June 2023 papers and came across this question in Paper 3. The question is attached. I do not understand Q3.2, so have included both the context of the question (if needed) and the Q3.2 I do not understand how to do, and don't understand how the mark scheme has done it.
One thing I am confused about is that to find the horizontal component of Magnetic Flux Density, why have they taken the vertical component in the mark scheme which is BHcos45.
I would appreciate it if someone could try to solve this question 3.2 and explain to me how they did it, since I am very confused.
Reply 1
12
the vertical component will vary with cos of the anglecos25 = 0.906 so the field strength goes from 100% to 90.6%, a change of 9.4%
pretty crap question though and the mark scheme is super confusing
pretty crap question though and the mark scheme is super confusing
Reply 2
Original post
by Thomas_02Hi everyone,
I am in Year 13 studying AQA Physics for A Level, was doing the June 2023 papers and came across this question in Paper 3. The question is attached. I do not understand Q3.2, so have included both the context of the question (if needed) and the Q3.2 I do not understand how to do, and don't understand how the mark scheme has done it.
One thing I am confused about is that to find the horizontal component of Magnetic Flux Density, why have they taken the vertical component in the mark scheme which is BHcos45.
I would appreciate it if someone could try to solve this question 3.2 and explain to me how they did it, since I am very confused.
I am in Year 13 studying AQA Physics for A Level, was doing the June 2023 papers and came across this question in Paper 3. The question is attached. I do not understand Q3.2, so have included both the context of the question (if needed) and the Q3.2 I do not understand how to do, and don't understand how the mark scheme has done it.
One thing I am confused about is that to find the horizontal component of Magnetic Flux Density, why have they taken the vertical component in the mark scheme which is BHcos45.
I would appreciate it if someone could try to solve this question 3.2 and explain to me how they did it, since I am very confused.
At 25°, the magnetic field of the coil will be less. To find the new strength, calculate that by multiplying the old strength with cosine of 25 degrees. So, B1 = B × cos(25°).
So to get the percentage change, you can use: Percentage Change = (1 − cos(25°)) × 100.
Since cos(25°) is roughly 0.9063, the math works out to:
Percentage Change = 9.37% approx.
Simply put, coil turns 25 degrees, and the magnetic field decreases to approximately 9.37%.
Kind regards from Italy,
Sandro
(edited 11 months ago)
Reply 3
7
Thank you both of you for helping! If I am need of any other assistance I will contact you again! @Drummy @Nitrotoluene
Reply 4
Original post
by Thomas_02Thank you both of you for helping! If I am need of any other assistance I will contact you again! @Drummy @Nitrotoluene
Thank you for your kind words.
I almost never get replies to my suggestions, even though they are correct. So I appreciate you taking the time to reply to what I suggested. You are one of the most polite, and I appreciate that you are active on the forum. Keep up!
Kind regards from Italy,
Sandro
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