maths question help please
hi, please could i have help on part d? I have no clue on how to calculate it, the normal distribution graph would start at t>2?
question: https://ibb.co/MDXb1qqZ
thanks!
question: https://ibb.co/MDXb1qqZ
thanks!
Reply 1
21
Original post
by anonymous56754hi, please could i have help on part d? I have no clue on how to calculate it, the normal distribution graph would start at t>2?
question: https://ibb.co/MDXb1qqZ
thanks!
question: https://ibb.co/MDXb1qqZ
thanks!
A sketch helps, but its still a pdf with the left tail, T<2, chopped off. So calculate the cumulative P(T>2) and divide/rescale the original normal pdf by that as
p(T | T>2) = p(T) / P(T>2)
Reply 2
13
Original post
by mqb2766A sketch helps, but its still a pdf with the left tail, T<2, chopped off. So calculate the cumulative P(T>2) and divide/rescale the original normal pdf by that as
p(T | T>2) = p(T) / P(T>2)
p(T | T>2) = p(T) / P(T>2)
Sorry what do you mean by pdf? Also, I'm unsure how to calculate because hasn't μ changed and that is what we are calculating as the median?
Reply 3
21
Original post
by anonymous56754Sorry what do you mean by pdf? Also, I'm unsure how to calculate because hasn't μ changed and that is what we are calculating as the median?
pdf is the probability density function p(x) so it integrates to unity
cdf is the cumulative density function P(x<X) so it goes from 0 to 1.
https://www.probabilitycourse.com/chapter4/4_2_3_normal.php
If you know P(T<2), what is P(T>2) and the median is the 50% of the new distribution p(T)/P(T>2) which you could work out in terms of the original distrbution by halving ... and ... A sketch really helps as youre cutting off the left tail then finding the midpoint of the remaining distribution (which is no longer symmetric, as the median, mean and mode is the same for a normal distribution).
(edited 11 months ago)
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