Maths variable acceleration
https://imgur.com/a/PL49AKj
Can someone help me with this question please?
I differentiated s to get v and found t as 1 and 5 for when it is at rest. I’m a bit thrown off when it says travelled in the negative x direction? Could anyone help me understand what they mean by that?
I found the area between 1 and 5 to be -32 and the answer is 32 but I don’t understand why?
Can someone help me with this question please?
I differentiated s to get v and found t as 1 and 5 for when it is at rest. I’m a bit thrown off when it says travelled in the negative x direction? Could anyone help me understand what they mean by that?
I found the area between 1 and 5 to be -32 and the answer is 32 but I don’t understand why?
Reply 1
21
Original post
by username79352https://imgur.com/a/PL49AKj
Can someone help me with this question please?
I differentiated s to get v and found t as 1 and 5 for when it is at rest. I’m a bit thrown off when it says travelled in the negative x direction? Could anyone help me understand what they mean by that?
I found the area between 1 and 5 to be -32 and the answer is 32 but I don’t understand why?
Can someone help me with this question please?
I differentiated s to get v and found t as 1 and 5 for when it is at rest. I’m a bit thrown off when it says travelled in the negative x direction? Could anyone help me understand what they mean by that?
I found the area between 1 and 5 to be -32 and the answer is 32 but I don’t understand why?
As the direction of travel is constant between times 1 and 5 (velocity is not zero), the
distance travelled = |displacement|
Note you didnt need to integrate the velocity, you could simply sub those times into the displacement equation to get 7 and -25 so the distance travelled is 32 (in the negative direction, so the negative sign)
https://www.desmos.com/calculator/p9xz9dyis1
Note if you integrate a negative velocity between 1 and 5, you must get a negative displacement. As integration returns the signed area between the curve and the x-axis and this is negative.
(edited 1 year ago)
Reply 2
Oh ok just the wording in the negative x direction sort of threw me off to be honest. Also for part b would it be 50m because the -25 is on the neg x axis and it would take 25 to get there and 25 to return giving 50 in total?
Reply 3
21
Original post
by username79352Oh ok just the wording in the negative x direction sort of threw me off to be honest. Also for part b would it be 50m because the -25 is on the neg x axis and it would take 25 to get there and 25 to return giving 50 in total?
Sounds ok for b). x(5)=-25 is the minimum displacement as v(5)=0
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