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A-Level Chemistry

Hi, I wanted to make some sort of a chart with periodic table trends(e.g bp in halogens group) for chemistry revision. Would anyone be interested in dropping any trends they came across during revision or from past paper questions down below this post? It would be great for revision purposes!

Reply 1

Original post
by bilal04
Hi, I wanted to make some sort of a chart with periodic table trends(e.g bp in halogens group) for chemistry revision. Would anyone be interested in dropping any trends they came across during revision or from past paper questions down below this post? It would be great for revision purposes!

Boiling Point(BP) in group 7 (Halogens):
Trend: BP increases as we go down the group
Explanation:
-As we go down the group the atomic radius increases as well as the number of shells
-The number of electrons increases
-This means greater induced dipole dipole forces/intermolecular forces (IMF)/ London forces
-The greater the forces the more energy required to break induced dipole dipole interaction/ intermolecular forces (IMF)/ London forces

Reply 2

Original post
by bilal04
Hi, I wanted to make some sort of a chart with periodic table trends(e.g bp in halogens group) for chemistry revision. Would anyone be interested in dropping any trends they came across during revision or from past paper questions down below this post? It would be great for revision purposes!

Hi! I’m Nally and currently studying Media, Communications and Sociology at City St George’s, University of London.
I have done Chemistry in A-levels and got a pretty good grade for my exam around 2 years ago. Here are some simple and key trends with periodic table:

1.

Atomic Radius: decrease across a period, increase down a group

2.

Ionization Energy: increase across a period, decrease down a group

3.

Electronegativity: increase across a period, decrease down a group

4.

Electron Affinity: increase across a period, decrease down a group

5.

Boiling Point of Halogens (group 7): increases as you go down
As you go down the group, the atomic radius increases, the number of electrons increases so the molecule becomes larger. This means a greater van der Waals forces, which require more energy to overcome, therefore a higher boiling point.

6.

Melting Point of Alkali Metals (Group 1): decreases as you go down
As atoms get larger down the group, and the ion size increases, the metallic bond (between positive ions and delocalized electrons) becomes weaker. The outer electron is further from the nucleus, so it is less tightly held, and it takes less energy to break the bond. That means a lower melting point is needed.

Hope that helps and good luck with your exam! 😊
(edited 10 months ago)

Reply 3

Original post
by NallyCityUniRep
Hi! I’m Nally and currently studying Media, Communications and Sociology at City St George’s, University of London.
I have done Chemistry in A-levels and got a pretty good grade for my exam around 2 years ago. Here are some simple and key trends with periodic table:

1.

Atomic Radius: decrease across a period, increase down a group

2.

Ionization Energy: increase across a period, decrease down a group

3.

Electronegativity: increase across a period, decrease down a group

4.

Electron Affinity: increase across a period, decrease down a group

5.

Boiling Point of Halogens (group 7): increases as you go down
As you go down the group, the atomic radius increases, the number of electrons increases so the molecule becomes larger. This means a greater van der Waals forces, which require more energy to overcome, therefore a higher boiling point.

6.

Melting Point of Alkali Metals (Group 1): decreases as you go down
As atoms get larger down the group, and the ion size increases, the metallic bond (between positive ions and delocalized electrons) becomes weaker. The outer electron is further from the nucleus, so it is less tightly held, and it takes less energy to break the bond. That means a lower melting point is needed.

Hope that helps and good luck with your exam! 😊

Thanks Nally, wish you all the best at Uni!

Reply 4

Original post
by NallyCityUniRep
Hi! I’m Nally and currently studying Media, Communications and Sociology at City St George’s, University of London.
I have done Chemistry in A-levels and got a pretty good grade for my exam around 2 years ago. Here are some simple and key trends with periodic table:

1.

Atomic Radius: decrease across a period, increase down a group

2.

Ionization Energy: increase across a period, decrease down a group

3.

Electronegativity: increase across a period, decrease down a group

4.

Electron Affinity: increase across a period, decrease down a group

5.

Boiling Point of Halogens (group 7): increases as you go down
As you go down the group, the atomic radius increases, the number of electrons increases so the molecule becomes larger. This means a greater van der Waals forces, which require more energy to overcome, therefore a higher boiling point.

6.

Melting Point of Alkali Metals (Group 1): decreases as you go down
As atoms get larger down the group, and the ion size increases, the metallic bond (between positive ions and delocalized electrons) becomes weaker. The outer electron is further from the nucleus, so it is less tightly held, and it takes less energy to break the bond. That means a lower melting point is needed.

Hope that helps and good luck with your exam! 😊

Whilst this is correct, it is worth pointing out that “van der Waals force” is actually an umbrella term for several kinds of IMF and so OCR (and possibly a few other exam boards) no longer accept it in their mark schemes. A better term to use would be “London dispersion force”.

To add on to the list of trends so far, I’ll add a few things that are of importance - especially in the second year of A levels:

-The boiling points of the hydrogen halides should in theory increase down the group (again, think London dispersion forces). This holds true for HCl - HI, but HF is anomalously high due to the strength of the hydrogen bonds it is able to form compared to the permanent dipole-dipole and London dispersion forces in the other hydrogen halides.

-The hydration enthalpies for the halide ions become less exothermic down the group because they become less charge dense and therefore the strength of the water-halide interactions weakens, hence the decreased release in energy. Additionally, fluoride forms H-bonds to water which makes the interactions even stronger yet.

-The lattice formation enthalpies for a series of halides of the same element in the same oxidation state (e.g NaF, NaCl, NaBr etc) should become less exothermic down the group due to the increasing anion size and the weaker attraction between the ions.

And as a bit of extra stuff that goes a little beyond the scope of A levels:

-Electron affinity generally does decrease down a group, but for group 7, fluorine doesn’t quite obey the trend - there is an increase from F to Cl, followed by a decrease down the group. This is due to fluorine’s small size leading to a greater repulsion between the gained electron and the electrons already in the outermost quantum shell.

-Bond enthalpies generally decrease down a group, but the halogen-halogen bond lengths follow an analogous trend to the electron affinities. Again, fluorine’s small size leads to greater lone pair-lone pair repulsion, which makes the F-F bond weaker than expected and this is in part why fluorine is so reactive.

Reply 5

Original post
by TypicalNerd
Whilst this is correct, it is worth pointing out that “van der Waals force” is actually an umbrella term for several kinds of IMF and so OCR (and possibly a few other exam boards) no longer accept it in their mark schemes. A better term to use would be “London dispersion force”.
To add on to the list of trends so far, I’ll add a few things that are of importance - especially in the second year of A levels:
-The boiling points of the hydrogen halides should in theory increase down the group (again, think London dispersion forces). This holds true for HCl - HI, but HF is anomalously high due to the strength of the hydrogen bonds it is able to form compared to the permanent dipole-dipole and London dispersion forces in the other hydrogen halides.
-The hydration enthalpies for the halide ions become less exothermic down the group because they become less charge dense and therefore the strength of the water-halide interactions weakens, hence the decreased release in energy. Additionally, fluoride forms H-bonds to water which makes the interactions even stronger yet.
-The lattice formation enthalpies for a series of halides of the same element in the same oxidation state (e.g NaF, NaCl, NaBr etc) should become less exothermic down the group due to the increasing anion size and the weaker attraction between the ions.
And as a bit of extra stuff that goes a little beyond the scope of A levels:
-Electron affinity generally does decrease down a group, but for group 7, fluorine doesn’t quite obey the trend - there is an increase from F to Cl, followed by a decrease down the group. This is due to fluorine’s small size leading to a greater repulsion between the gained electron and the electrons already in the outermost quantum shell.
-Bond enthalpies generally decrease down a group, but the halogen-halogen bond lengths follow an analogous trend to the electron affinities. Again, fluorine’s small size leads to greater lone pair-lone pair repulsion, which makes the F-F bond weaker than expected and this is in part why fluorine is so reactive.

You are absolutely right with what you said on Van Der Waals force and OCR emphasises on the use of London Forces and not Van Der Waals in their examiner's reports. Thanks for pointing this out and thank you for adding on to the list of trends!

Reply 6

Hi I need some help with enthalpy changes: after you do q=mcdelta t and you find the enthalpy change using q and the moles. How do you know what moles to use because sometimes there more than 1 compound to calculate mole from

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