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A level maths

A rope is passed over a smooth beam. Two children, the heavier of which has mass 60 kg, hang on to the rope, one on either end, so that the heavier one descends with an acceleration of 2 ms-2. The mass of the lighter child, to the nearest kilogram, is.....kg

Reply 1

Original post
by Foresterrr
A rope is passed over a smooth beam. Two children, the heavier of which has mass 60 kg, hang on to the rope, one on either end, so that the heavier one descends with an acceleration of 2 ms-2. The mass of the lighter child, to the nearest kilogram, is.....kg


It would be great that you explain what is the problem that you are facing in doing this problem.

It is always good to draw a simple diagram (aka free-body diagram) to show all the forces acting on the heavier child.

Recall N2L as Fnet = ma.

Can you continue from here?

Reply 2

Original post
by Foresterrr
A rope is passed over a smooth beam. Two children, the heavier of which has mass 60 kg, hang on to the rope, one on either end, so that the heavier one descends with an acceleration of 2 ms-2. The mass of the lighter child, to the nearest kilogram, is.....kg

It is best to do it yourself.
Here's a tip:
Okay, so for the heavier kid: There is gravity pulling them downwards. To find that force, use their mass (m1 = 60 kg) and acceleration due to gravity (g = 9.8 ms^-2). The rope's also pulling up on them. We refer to that force as tension. Let's refer to how strong it is.
Now, for the lighter child: The same thing, gravity's attracting them downward. Let's set their mass to m2.
Once more, the rope is subjected to an upward force due to tension (T). If the rope is ideal and the beam is smooth, what can be said about the tension and tension experienced by the heavier child?
Use Newton's Second Law (F=mg) for both cases. For each child, consider the forces pulling them downwards and the forces pulling them upwards (give opposite signs for acceleration).
Find the tension (T) and mass of a lighter child. Check the consistency of your units. Let me know if you need help!
Here is my 2 cents!

Reply 3

Original post
by Nitrotoluene
.....
Use Newton's Second Law (F=mg) for both cases.
...


We don't write Newton's Second Law as F = mg, in fact, mg is the weight NOT net force.

Reply 4

Original post
by Eimmanuel
We don't write Newton's Second Law as F = mg, in fact, mg is the weight NOT net force.

Hello, Eimmanuel!
I have checked my suggestions carefully and you are right about Newton's second law.
However, it seems to me that with some more information, such as knowing the speed at which the system is accelerating (a), I think we could solve the problem by understanding the tension (T) and the mass of the lighter child (m2).
What do you think of my comment above?

Bye,
Sandro

Reply 5

Original post
by Nitrotoluene
Hello, Eimmanuel!
I have checked my suggestions carefully and you are right about Newton's second law.
However, it seems to me that with some more information, such as knowing the speed at which the system is accelerating (a), I think we could solve the problem by understanding the tension (T) and the mass of the lighter child (m2).
What do you think of my comment above?

Bye,
Sandro


We don't need to know the speed as Fnet is related to acceleration NOT speed.

In fact, we can solve the problem in a "single step".

This is a modified Atwood Machine problem.

We shall let OP respond to the replies first before making additional comments.

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