Edexcel AS Level Maths May 15th 2025 Pure Paper 1 + Unofficial Mark Scheme

Unofficial mark scheme:
Credit to: @Jeff1527383
1i) A(-3,0) B(0,7) Asymptote y=3
ii) A(-1,0) B(2,-7) Asymptote y=-3
2a ) y=4x+12
b) {y:2x^2+5x-3 <= y<4x+12}
3a) 2sqrt(10)
b)47.6°
4a) Centre (-5, 2), radius sqrt(28)
b)2-2sqrt(7)<k<2+2sqrt(7)
Everyone pls feel free to contribute!

for 4b it needs to be in set notation {k:k>2-sqrt(7)}U{k:k<2+2sqrt(7)}

just found the paper. Search up riadmathsy on tiktok

Yes I know but didn’t want to write that out. However your correction is wrong. The set of values you just provided is the entire real line. The U symbol should be upside down, it’s an intersection not a union.
Alternatively you can write it as {k: 2-2root7 < k < 2+2root7}

no isnt it an intersection because both conditions hast to be true at once. if it was less than 2+2sqrt(7) then it could be -5.

Cool, so do you still need me to post the answers?

Yes both need to be true at once, that is EXACTLY why it is an intersection. I think you need to revise your set notation.
You are correct in what you’ve said, but clearly have unions and intersections confused.

Can u do question 8 pls the trig one

Sin^2(3x) = 4Cos^2(3x)
Divide both sides by Cos^2(3x) to get:
Tan^2(3x) = 4
Therefore
Tan(3x) = 2 or Tan(3x) = -2
Solve for 0 < 3x < 270 to get the 3 solutions:
x = 21.1, 38.9, 81.1

Yk for question 13 modding with logs, i got part a wrong ( i think i still got like 1-2 marks) but for the other parts i used the wrong values but my methods was 100% fine. Would i get any marks even though my answers were not right?

Unofficial mark scheme:
Credit to: @Jeff1527383
1i) A(-3,0) B(0,7) Asymptote y=3
ii) A(-1,0) B(2,-7) Asymptote y=-3
2a) y=4x+12
b) {y : 2x^2+5x-3 <= y < 4x+12}
3a) 2sqrt(10)
b) 47.6 degrees
4a)Centre (-5, 2), radius sqrt(28)
b) {k: 2-2sqrt(7)<k<2+2sqrt(7)}
5a) f(x) = 1/4 x^4 - 3x^(-1/2)
b) x^5/20 - 6x^(1/2) + C
6a) Sub in x=-3 and set equal to 0. Rearrange for -3a+b = 5
b) a=-1, b=2
7a) profit would be negative
b) Max x = 145.81
c) a=450, b=-1, c=-130
di) £450,000
dii) £130
8) x = 21.1, 38.9, 81.1
9) use b^2-4ac=0, rearrange for q
10) x=5, only answer (reject x=-4)
11a) show that question, just find an equation for A and for V in terms of L and substitute one into the other.
b) 44.8cm
c) find second derivative to be 6pi > 0 thus minimum
d) £56.78
e) Assume you can pay for the exact amount used and not need to buy two whole sheets when only 1.89 are used.
12a) sketch a positive quadratic with roots at -3 and 0
b) dy/dx = 3x^2 + 9x
13a) h = 31 - 31.3e^(-0.0223t), {a = 31.3, k = 0.0223}
b) 31
ci) -0.3m
cii) Not suitable as the tree cannot have negative height
di) dh/dt = 0.69799e^(-0.0223t)
dii) 37.9 years (1 dp)
14a) p = 28k^2
b) pairs are (a=3, k=3/2) and (a=-23/3, k=5/6)
15a) Sometimes true
b) Never true

Here are the full answers:
1i) A(-3,0) B(0,7) Asymptote y=3
ii) A(-1,0) B(2,-7) Asymptote y=-3
2a) y=4x+12
b) {y : 2x^2+5x-3 <= y < 4x+12}
3a) 2sqrt(10)
b) 47.6 degrees
4a)Centre (-5, 2), radius sqrt(28)
b) {k: 2-2sqrt(7)<k<2+2sqrt(7)}
5a) f(x) = 1/4 x^4 - 3x^(-1/2)
b) x^5/20 - 6x^(1/2) + C
6a) Sub in x=-3 and set equal to 0. Rearrange for -3a+b = 5
b) a=-1, b=2
7a) profit would be negative
b) Max x = 145.81
c) a=450, b=-1, c=-130
di) £450,000
dii) £130
8) x = 21.1, 38.9, 81.1
9) use b^2-4ac=0, rearrange for q
10) x=5, only answer (reject x=-4)
11a) show that question, just find an equation for A and for V in terms of L and substitute one into the other.
b) 44.8cm
c) find second derivative to be 6pi > 0 thus minimum
d) £56.78
e) Assume you can pay for the exact amount used and not need to buy two whole sheets when only 1.89 are used.
12a) sketch a positive quadratic with roots at -3 and 0
b) dy/dx = 3x^2 + 9x
13a) h = 31 - 31.3e^(-0.0223t), {a = 31.3, k = 0.0223}
b) 31
ci) -0.3m
cii) Not suitable as the tree cannot have negative height
di) dh/dt = 0.69799e^(-0.0223t)
dii) 37.9 years (1 dp)
14a) p = 28k^2
b) pairs are (a=3, k=3/2) and (a=-23/3, k=5/6)
15a) Sometimes true
b) Never true

what did everyone get for the trigonometric identities ??

can u explain q12

Hello,
Did anyone get x=10cm for the minimum value for the cylinder?

No, it was 44.8cm

I feel I have go over 60 out of 100. What grade would that equate to?