Edexcel AS Level Maths May 15th 2025 Pure Paper 1 + Unofficial Mark Scheme

Probably as i said the trend i have seen is that 65 has been the highest in this syllabus

Is there anywhere where I can see the individual marks needed for paper 1 and 2. As the Edexcel grade boundaries just show the overall marks?

Is there anywhere where I can see the individual marks needed for paper 1 and 2. As the Edexcel grade boundaries just show the overall marks?

Do you think the grade boundaries will be lower for that paper?

Unofficial mark scheme:
Credit to: @Jeff1527383
1i) A(-3,0) B(0,7) Asymptote y=3
ii) A(-1,0) B(2,-7) Asymptote y=-3
2a) y=4x+12
b) {y : 2x^2+5x-3 <= y < 4x+12}
3a) 2sqrt(10)
b) 47.6 degrees
4a)Centre (-5, 2), radius sqrt(28)
b) {k: 2-2sqrt(7)<k<2+2sqrt(7)}
5a) f(x) = 1/4 x^4 - 3x^(-1/2)
b) x^5/20 - 6x^(1/2) + C
6a) Sub in x=-3 and set equal to 0. Rearrange for -3a+b = 5
b) a=-1, b=2
7a) profit would be negative
b) Max x = 145.81
c) a=450, b=-1, c=-130
di) £450,000
dii) £130
8) x = 21.1, 38.9, 81.1
9) use b^2-4ac=0, rearrange for q
10) x=5, only answer (reject x=-4)
11a) show that question, just find an equation for A and for V in terms of L and substitute one into the other.
b) 44.8cm
c) find second derivative to be 6pi > 0 thus minimum
d) £56.78
e) Assume you can pay for the exact amount used and not need to buy two whole sheets when only 1.89 are used.
12a) sketch a positive quadratic with roots at -3 and 0
b) dy/dx = 3x^2 + 9x
13a) h = 31 - 31.3e^(-0.0223t), {a = 31.3, k = 0.0223}
b) 31
ci) -0.3m
cii) Not suitable as the tree cannot have negative height
di) dh/dt = 0.69799e^(-0.0223t)
dii) 37.9 years (1 dp)
14a) p = 28k^2
b) pairs are (a=3, k=3/2) and (a=-23/3, k=5/6)
15a) Sometimes true
b) Never true

I got the same but I refused to believe A was 31.3 (so close to 31 which was in the equation already) so I thought i got it wrong and gave up and didn’t do the rest of the questions 😭

Do you know if anyone has posted a stats and mechanic mark scheme?

not great, some of the questions were SO bad - wdym sketch the curve of the gradient of a random cubic?!

Unofficial mark scheme:
Credit to: @Jeff1527383
1i) A(-3,0) B(0,7) Asymptote y=3
ii) A(-1,0) B(2,-7) Asymptote y=-3
2a) y=4x+12
b) {y : 2x^2+5x-3 <= y < 4x+12}
3a) 2sqrt(10)
b) 47.6 degrees
4a)Centre (-5, 2), radius sqrt(28)
b) {k: 2-2sqrt(7)<k<2+2sqrt(7)}
5a) f(x) = 1/4 x^4 - 3x^(-1/2)
b) x^5/20 - 6x^(1/2) + C
6a) Sub in x=-3 and set equal to 0. Rearrange for -3a+b = 5
b) a=-1, b=2
7a) profit would be negative
b) Max x = 145.81
c) a=450, b=-1, c=-130
di) £450,000
dii) £130
8) x = 21.1, 38.9, 81.1
9) use b^2-4ac=0, rearrange for q
10) x=5, only answer (reject x=-4)
11a) show that question, just find an equation for A and for V in terms of L and substitute one into the other.
b) 44.8cm
c) find second derivative to be 6pi > 0 thus minimum
d) £56.78
e) Assume you can pay for the exact amount used and not need to buy two whole sheets when only 1.89 are used.
12a) sketch a positive quadratic with roots at -3 and 0
b) dy/dx = 3x^2 + 9x
13a) h = 31 - 31.3e^(-0.0223t), {a = 31.3, k = 0.0223}
b) 31
ci) -0.3m
cii) Not suitable as the tree cannot have negative height
di) dh/dt = 0.69799e^(-0.0223t)
dii) 37.9 years (1 dp)
14a) p = 28k^2
b) pairs are (a=3, k=3/2) and (a=-23/3, k=5/6)
15a) Sometimes true
b) Never true

Unofficial mark scheme:
Credit to: @Jeff1527383
1i) A(-3,0) B(0,7) Asymptote y=3
ii) A(-1,0) B(2,-7) Asymptote y=-3
2a) y=4x+12
b) {y : 2x^2+5x-3 <= y < 4x+12}
3a) 2sqrt(10)
b) 47.6 degrees
4a)Centre (-5, 2), radius sqrt(28)
b) {k: 2-2sqrt(7)<k<2+2sqrt(7)}
5a) f(x) = 1/4 x^4 - 3x^(-1/2)
b) x^5/20 - 6x^(1/2) + C
6a) Sub in x=-3 and set equal to 0. Rearrange for -3a+b = 5
b) a=-1, b=2
7a) profit would be negative
b) Max x = 145.81
c) a=450, b=-1, c=-130
di) £450,000
dii) £130
8) x = 21.1, 38.9, 81.1
9) use b^2-4ac=0, rearrange for q
10) x=5, only answer (reject x=-4)
11a) show that question, just find an equation for A and for V in terms of L and substitute one into the other.
b) 44.8cm
c) find second derivative to be 6pi > 0 thus minimum
d) £56.78
e) Assume you can pay for the exact amount used and not need to buy two whole sheets when only 1.89 are used.
12a) sketch a positive quadratic with roots at -3 and 0
b) dy/dx = 3x^2 + 9x
13a) h = 31 - 31.3e^(-0.0223t), {a = 31.3, k = 0.0223}
b) 31
ci) -0.3m
cii) Not suitable as the tree cannot have negative height
di) dh/dt = 0.69799e^(-0.0223t)
dii) 37.9 years (1 dp)
14a) p = 28k^2
b) pairs are (a=3, k=3/2) and (a=-23/3, k=5/6)
15a) Sometimes true
b) Never true

just found the paper. Search up riadmathsy on tiktok

Unofficial mark scheme:
Credit to: @Jeff1527383
1i) A(-3,0) B(0,7) Asymptote y=3
ii) A(-1,0) B(2,-7) Asymptote y=-3
2a) y=4x+12
b) {y : 2x^2+5x-3 <= y < 4x+12}
3a) 2sqrt(10)
b) 47.6 degrees
4a)Centre (-5, 2), radius sqrt(28)
b) {k: 2-2sqrt(7)<k<2+2sqrt(7)}
5a) f(x) = 1/4 x^4 - 3x^(-1/2)
b) x^5/20 - 6x^(1/2) + C
6a) Sub in x=-3 and set equal to 0. Rearrange for -3a+b = 5
b) a=-1, b=2
7a) profit would be negative
b) Max x = 145.81
c) a=450, b=-1, c=-130
di) £450,000
dii) £130
8) x = 21.1, 38.9, 81.1
9) use b^2-4ac=0, rearrange for q
10) x=5, only answer (reject x=-4)
11a) show that question, just find an equation for A and for V in terms of L and substitute one into the other.
b) 44.8cm
c) find second derivative to be 6pi > 0 thus minimum
d) £56.78
e) Assume you can pay for the exact amount used and not need to buy two whole sheets when only 1.89 are used.
12a) sketch a positive quadratic with roots at -3 and 0
b) dy/dx = 3x^2 + 9x
13a) h = 31 - 31.3e^(-0.0223t), {a = 31.3, k = 0.0223}
b) 31
ci) -0.3m
cii) Not suitable as the tree cannot have negative height
di) dh/dt = 0.69799e^(-0.0223t)
dii) 37.9 years (1 dp)
14a) p = 28k^2
b) pairs are (a=3, k=3/2) and (a=-23/3, k=5/6)
15a) Sometimes true
b) Never true

Does someone have the actual exam paper for AS 2025 plss

Can you pls upload the unofficial mark scheme for paper 2???

Do you know if anyone has posted a stats and mechanic mark scheme?

Unofficial mark scheme:
Credit to: @Jeff1527383
1i) A(-3,0) B(0,7) Asymptote y=3
ii) A(-1,0) B(2,-7) Asymptote y=-3
2a) y=4x+12
b) {y : 2x^2+5x-3 <= y < 4x+12}
3a) 2sqrt(10)
b) 47.6 degrees
4a)Centre (-5, 2), radius sqrt(28)
b) {k: 2-2sqrt(7)<k<2+2sqrt(7)}
5a) f(x) = 1/4 x^4 - 3x^(-1/2)
b) x^5/20 - 6x^(1/2) + C
6a) Sub in x=-3 and set equal to 0. Rearrange for -3a+b = 5
b) a=-1, b=2
7a) profit would be negative
b) Max x = 145.81
c) a=450, b=-1, c=-130
di) £450,000
dii) £130
8) x = 21.1, 38.9, 81.1
9) use b^2-4ac=0, rearrange for q
10) x=5, only answer (reject x=-4)
11a) show that question, just find an equation for A and for V in terms of L and substitute one into the other.
b) 44.8cm
c) find second derivative to be 6pi > 0 thus minimum
d) £56.78
e) Assume you can pay for the exact amount used and not need to buy two whole sheets when only 1.89 are used.
12a) sketch a positive quadratic with roots at -3 and 0
b) dy/dx = 3x^2 + 9x
13a) h = 31 - 31.3e^(-0.0223t), {a = 31.3, k = 0.0223}
b) 31
ci) -0.3m
cii) Not suitable as the tree cannot have negative height
di) dh/dt = 0.69799e^(-0.0223t)
dii) 37.9 years (1 dp)
14a) p = 28k^2
b) pairs are (a=3, k=3/2) and (a=-23/3, k=5/6)
15a) Sometimes true
b) Never true

Does someone have the actual exam paper for AS 2025 plss