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URGENT PHYSICS HELP PLEASE thank you

Please could I have help on question 6d ii. I understand that the current increases so using v=e-ir since everything else is constant, terminal pd would decrease. Why does the ms say the pd across internal resistance increases?
https://pmt.physicsandmathstutor.com/download/Physics/A-level/Past-Papers/CAIE/Paper-2/QP/June%202024%20(v1)%20QP.pdf
Thanks

Reply 1

Original post
by anonymous56754
Please could I have help on question 6d ii. I understand that the current increases so using v=e-ir since everything else is constant, terminal pd would decrease. Why does the ms say the pd across internal resistance increases?
https://pmt.physicsandmathstutor.com/download/Physics/A-level/Past-Papers/CAIE/Paper-2/QP/June%202024%20(v1)%20QP.pdf
Thanks

Alright, so you see that the addition of the third resistor does make a difference! You're correct, the overall current does go up when R3 is in parallel.
Now, think about the internal resistance, r. Remember Ohm's Law? What does the current through r do to the voltage across it? If you change the current, what are you doing to the voltage drop across the internal resistance?
PS: A coherent answer according to the TSR rules.
Krgds,
Sandro
(edited 8 months ago)

Reply 2

Original post
by anonymous56754
Please could I have help on question 6d ii. I understand that the current increases so using v=e-ir since everything else is constant, terminal pd would decrease. Why does the ms say the pd across internal resistance increases?
https://pmt.physicsandmathstutor.com/download/Physics/A-level/Past-Papers/CAIE/Paper-2/QP/June%202024%20(v1)%20QP.pdf
Thanks


Hope, it is not too late.

When current increases, not everything remains the same in terminal p.d. = emf - Ir.

When current increases, the quantity Ir will increase - a larger current multiplies a constant internal resistance gives a larger p.d. across the internal resistor.

Reply 3

Original post
by Eimmanuel
Hope, it is not too late.
When current increases, not everything remains the same in terminal p.d. = emf - Ir.
When current increases, the quantity Ir will increase - a larger current multiplies a constant internal resistance gives a larger p.d. across the internal resistor.

Ohhh thank you so much I get it now! I have my exam later this afternoon hence the urgency😅

Reply 4

Original post
by Nitrotoluene
Alright, so you see that the addition of the third resistor does make a difference! You're correct, the overall current does go up when R3 is in parallel.
Now, think about the internal resistance, r. Remember Ohm's Law? What does the current through r do to the voltage across it? If you change the current, what are you doing to the voltage drop across the internal resistance?
PS: A coherent answer according to the TSR rules.
Krgds,
Sandro

thank you!!

Reply 5

Original post
by anonymous56754
thank you!!


Original post
by anonymous56754
Ohhh thank you so much I get it now! I have my exam later this afternoon hence the urgency😅


Be at peace and use "common sense" and do the paper steadily and you will make it. :smile:

Don't need to be the first rat to complete the paper, and do what you can do first.

Reply 6

Original post
by Eimmanuel
Be at peace and use "common sense" and do the paper steadily and you will make it. :smile:
Don't need to be the first rat to complete the paper, and do what you can do first.

Thank you, I'll try my best ☺️

Reply 7

"Keep calm!"💯
Ciao,
Sandro

Reply 8

Original post
by Nitrotoluene
"Keep calm!"💯
Ciao,
Sandro
Thanks :smile:

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