michelson morley a level aqa turning points physics
In the michelson morley experiment what was the point in the two rays travelling through the same thickness of glass and air if they were going to have a path difference in order to produce an interference pattern?
Shouldnt they have a slightly different path?
Or was it only hypothesized that there would be a path difference due to one ray travelling with the wind and it was in fact the same distance?
Shouldnt they have a slightly different path?
Or was it only hypothesized that there would be a path difference due to one ray travelling with the wind and it was in fact the same distance?
Reply 1
'wind' do you mean 'ether'?
All features of the two paths had to be equal to check if there was an effect by only the ether.
All features of the two paths had to be equal to check if there was an effect by only the ether.
Reply 2
63737
OP
4
Original post
by tarmac-the-cat'wind' do you mean 'ether'?
All features of the two paths had to be equal to check if there was an effect by only the ether.
All features of the two paths had to be equal to check if there was an effect by only the ether.
Thanks for answering,
then as there is no ether how is it that there was initially an interference pattern as wouldnt the two rays have travelled the same distance?
Reply 3
Original post
by 63737Thanks for answering,
then as there is no ether how is it that there was initially an interference pattern as wouldnt the two rays have travelled the same distance?
then as there is no ether how is it that there was initially an interference pattern as wouldnt the two rays have travelled the same distance?
Having no path difference or the 2 rays travelling the same distance does not mean no interference.
When the path difference is zero, it means that there will be a bright fringe instead of a dark fringe.
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