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Thread starter 14 years ago
#1
the points A(-3,-2) and B(8,4) are at the ends of a diameter of a circle.
a)find the co-ordinates of the circle
b) find an equation of the diameter AB, giving your answer in the form ax+by+c=0
c) find an equation of tangent to the circle at B

---> main problem is part D
d) the line L passes through A and the origin. find the co-ords of the point at which L intersecs the tangent to the circle at B, giving your answer as exact fractions.

Thanks!! 0
14 years ago
#2
(Original post by Fizzle)
the points A(-3,-2) and B(8,4) are at the ends of a diameter of a circle.
a)find the co-ordinates of the circle
b) find an equation of the diameter AB, giving your answer in the form ax+by+c=0
c) find an equation of tangent to the circle at B

---> main problem is part D
d) the line L passes through A and the origin. find the co-ords of the point at which L intersecs the tangent to the circle at B, giving your answer as exact fractions.

Thanks!! Equation for L is 3y = 2x
find where this intersects with answer to (c)

Aitch
0
14 years ago
#3
(Original post by Aitch)
Equation for L is 3y = 2x
find where this intersects with answer to (c)

Aitch
I get 6y = 112 - 11x as tangent...
call L 6y = 4x

so 112 - 11x = 4x etc

some messy fractions.

Aitch
0
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