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stu_724
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#1
Report Thread starter 14 years ago
#1
Hi i know this is the wrong forum but i need help!!!

I have a question I don’t even know where to start with, it is as follows:

Given the integral between 0 and infinity of sin ax / sinh bx = (pie/2b) * tanh * ((pie *a)/ 2b ) calculate…

The integral between 0 and infinity of cos ax / sinh bx dx

I mean what should I do can I just swap the cos ax for a relationship with sin ax if so what??

Or do I just perform the integration, how would I do this and what is the answer??

Thanks
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heminder
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#2
Report 14 years ago
#2
(Original post by stu_724)
Hi i know this is the wrong forum but i need help!!!

I have a question I don’t even know where to start with, it is as follows:

Given the integral between 0 and infinity of sin ax / sinh bx = (pie/2b) * tanh * ((pie *a)/ 2b ) calculate…

The integral between 0 and infinity of cos ax / sinh bx dx

I mean what should I do can I just swap the cos ax for a relationship with sin ax if so what??

Or do I just perform the integration, how would I do this and what is the answer??

Thanks
why don't you ask the Maths Department instead of the General Chat Department?
i would like to help you with the Maths bit, but i don't think that's my level (yet)...
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Aitch
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#3
Report 14 years ago
#3
(Original post by stu_724)
Hi i know this is the wrong forum but i need help!!!

I have a question I don’t even know where to start with, it is as follows:

Given the integral between 0 and infinity of sin ax / sinh bx = (pie/2b) * tanh * ((pie *a)/ 2b ) calculate…

The integral between 0 and infinity of cos ax / sinh bx dx

I mean what should I do can I just swap the cos ax for a relationship with sin ax if so what??

Or do I just perform the integration, how would I do this and what is the answer??

Thanks
It IS the wrong forum!

Go for the Maths guys!

Aitch
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