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BPhO1 2023 Paper 1 Part h

h) A glass block, with a reflecting lower surface, is shaped as a rectangular slab but whose
left and right sides are curved in the shape of quarter circles of radius 𝑅, as shown in
Fig. 3. The base A ray of light enters horizontally from the left and passes out through
the right side of the block at the same height above the base. The length of the top plane
surface is ℓ.

If the depth of the block is 2.0 cm and the refractive index 𝑛 = 1.46, what would be the
minimum value of to satisfy this situation?


Isn't the length of the block irrelevant? the question never states at what height the ray enters, so if it enters at depth zero no refraction will occur and it passes straight through. Doesn't this satisfy all the conditions?

Reply 1

Original post
by NewbieGaming123
h) A glass block, with a reflecting lower surface, is shaped as a rectangular slab but whose
left and right sides are curved in the shape of quarter circles of radius 𝑅, as shown in
Fig. 3. The base A ray of light enters horizontally from the left and passes out through
the right side of the block at the same height above the base. The length of the top plane
surface is ℓ.

If the depth of the block is 2.0 cm and the refractive index 𝑛 = 1.46, what would be the
minimum value of to satisfy this situation?


Isn't the length of the block irrelevant? the question never states at what height the ray enters, so if it enters at depth zero no refraction will occur and it passes straight through. Doesn't this satisfy all the conditions?



Original post
by NewbieGaming123
Isn't the length of the block irrelevant?


Without the relevant diagram or figure, how can we answer or explain it?

Original post
by NewbieGaming123
the question never states at what height the ray enters,


If height is not given, you can assume a value that will cancel out in the computation.

Again, without the relevant diagram or figure, I don’t really know for sure about the setup.

Original post
by NewbieGaming123
so if it enters at depth zero no refraction will occur and it passes straight through. Doesn't this satisfy all the conditions?


This can happen, but it may be a trivial case.


Upload the whole question instead of discarding important diagram or figure.
Or you can put a link in the thread that link to the question.

Reply 2

Original post
by Eimmanuel
Without the relevant diagram or figure, how can we answer or explain it?
If height is not given, you can assume a value that will cancel out in the computation.
Again, without the relevant diagram or figure, I don’t really know for sure about the setup.
This can happen, but it may be a trivial case.
Upload the whole question instead of discarding important diagram or figure.
Or you can put a link in the thread that link to the question.

Screenshot 2025-10-24 142332.png

Sorry for the lack of a diagram. I can come to terms with the "correct" solution, which is where the ray after refracting takes on the steepest possible gradient, which is the critical angle. However the bit I think is a bit ambigious is that a ray travelling along the reflective surface would also emerge parallel to the incident ray. Is this a bit pedantic or is the question poorly designed?

Reply 3

Original post
by NewbieGaming123
Screenshot 2025-10-24 142332.png

Sorry for the lack of a diagram. I can come to terms with the "correct" solution, which is where the ray after refracting takes on the steepest possible gradient, which is the critical angle. However the bit I think is a bit ambigious is that a ray travelling along the reflective surface would also emerge parallel to the incident ray. Is this a bit pedantic or is the question poorly designed?


I think you are over-analysing the problem and over-concerned about the trivial solution.

The trivial solution is that the ray passes parallel to the interface (boundary between the surface and the glass block)

I believe most physics problems (may be all) have trivial solutions if we look into them "deeply".

Reply 4

Nah, length isn’t irrelevant.
The ray comes in from the curved side, not the top. Those sides are quarter circles, so the light hits at an angle it has to refract. The block’s length decides if, after bouncing off the mirror bottom, it can leave the right side at the same height.
If ℓ’s too short, it’ll miss the exit point. Your “depth zero” idea doesn’t work ’cause that’d mean it never actually enters through the curved surface.

DM if you need more help - former Top Gold!

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