A level maths chapter 10
Solve the equation 4sinxcosx - cos^2x + 4sinx - cos x, range 0 - 360 degrees
I’ve done everything up till the point I factoride and got (4sinc - cosx) (cosx + 1) then got one answer for x to be 180 using cosx =-1, I’m unsure how to figure out the rest
I’ve done everything up till the point I factoride and got (4sinc - cosx) (cosx + 1) then got one answer for x to be 180 using cosx =-1, I’m unsure how to figure out the rest
Reply 1
Method 1) turn the 4sinx - cosx into the form of Rsin(x+A), where R and A are constants, then u can easily solve it for x.
Method 2) 4sinx=cosx, divided by cosx on both sides and you will only have one trig function in play
Method 2) 4sinx=cosx, divided by cosx on both sides and you will only have one trig function in play
Reply 2
16
Original post
by ToomanyennySolve the equation 4sinxcosx - cos^2x + 4sinx - cos x, range 0 - 360 degrees
I’ve done everything up till the point I factoride and got (4sinc - cosx) (cosx + 1) then got one answer for x to be 180 using cosx =-1, I’m unsure how to figure out the rest
I’ve done everything up till the point I factoride and got (4sinc - cosx) (cosx + 1) then got one answer for x to be 180 using cosx =-1, I’m unsure how to figure out the rest
What you've posted isn't an equation - is there supposed to be an "= 0" or something on the right hand side?
If you want to solve 4sinx - cosx = 0 then the easiest thing to do is divide both sides by cos x (why is it OK to divide by cos x?) and then you have tan x = something to solve which is just a calculator exercise
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