Using a quadratic graph to solve another.

Howdy. I am not sure how to answer this. I could complete the square and sketch it but it says use the graph given so don't think I could do that method.
Thanks

The original equation is y=x^2 -3 and the equation you want to solve is x^2-2x-2.
To solve it, you need to find the equation of a line such that x^2-3 = (equation of the line) can be rearranged to x^2-2x-2. Your values of x, for your solution, will be where your linear graph intersects the quadratic (which will be how you use the graph given to solve for x^2-2x-2).

Thanks but I don't understand. The line is y=0? How would I rearrange that to get x^2 -2x -2?

You can work backwards from x^2 -2x -2 to make it into x^2-3.
For example, if I were to do the working out:
x^2-2x-2=0
x^2-2=2x (2x is added on either side)
x^2-3 = 2x-1 (1 is subtracted from both sides)
Therefore, the linear line you have to draw and find the intersects with the quadratic graph is y=2x-1