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Matrices

Hi I’ve just started matrices a level cp1 edexcel and was wondering if someone could explain to me how the matrix ( 1 a ) all to the power of k is
(0 1 )
Worked out. My teacher just presented it and said this is the answer but I don’t know how to get it. I was kinda thinking that you apply the power to each value in the matrix but then I don’t get how a to the power of k is ak

Reply 1

Sorry the matrix is (1a for the first row and then 01 for the second row all to the power of k

Reply 2

Original post
by username79352
Sorry the matrix is (1a for the first row and then 01 for the second row all to the power of k

This just follows from the definition of matrix multiplication.

Can you work out the square of the matrix first to see where a '2a' would come from? Then multiply the new matrix by the original one to see how you get a '3a'? Then it's just following a pattern.

Reply 3

Original post
by username79352
Hi I’ve just started matrices a level cp1 edexcel and was wondering if someone could explain to me how the matrix ( 1 a ) all to the power of k is
(0 1 )
Worked out. My teacher just presented it and said this is the answer but I don’t know how to get it. I was kinda thinking that you apply the power to each value in the matrix but then I don’t get how a to the power of k is ak

Please can you write this out in LaTex/Mathjax or smth similar or submit an image + use exact wording of question? I can't tell what you're asking

Reply 4

Original post
by AltAccount00
Please can you write this out in LaTex/Mathjax or smth similar or submit an image + use exact wording of question? I can't tell what you're asking

I think they mean

\begin{pmatrix}1 & a\\0 & 1\end{pmatrix}

raised to the power k, so it's just a matter of doing "normal" matrix multiplication and spotting the pattern :smile:

Reply 5

Original post
by davros
This just follows from the definition of matrix multiplication.
Can you work out the square of the matrix first to see where a '2a' would come from? Then multiply the new matrix by the original one to see how you get a '3a'? Then it's just following a pattern.


Yeah I got the pattern thanks it came up in a later question but I was confused without going through it when they just said this is this. But thank you so much!!! :smile:

Reply 6

Original post
by davros
I think they mean
\begin{pmatrix}1 & a\\0 & 1\end{pmatrix}
raised to the power k, so it's just a matter of doing "normal" matrix multiplication and spotting the pattern :smile:


Yeah this was it!

Reply 7

Original post
by davros
I think they mean
\begin{pmatrix}1 & a\\0 & 1\end{pmatrix}
raised to the power k, so it's just a matter of doing "normal" matrix multiplication and spotting the pattern :smile:

Ohh, thanks. In that case your comment is as helpful as it can get without giving away answer

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