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# AEA maths question watch

1. I'm nowhere near AEA standard but I was looking at some old papers to see how hard they are and I saw an interesting one.

http://www.mathsexams.ukteachers.com...l/AEA_2004.pdf

Question 4(a)(i)
Can anyone post a solution?
2. (Original post by Widowmaker)
I'm nowhere near AEA standard but I was looking at some old papers to see how hard they are and I saw an interesting one.

http://www.mathsexams.ukteachers.com...l/AEA_2004.pdf

Question 4(a)(i)
Can anyone post a solution?
I get r = 2.

I think I need a diagram.

Aitch
3. (0,4) to centre is the same as perpendicular from centre to the tangent.... both are length r
let the tangential point be called t

the length from the origin to t is 4 (y axis is also a tangent, length of tangents from the same origin to where they touch the circle is the same)

equation of line is 4y - 3x = 0, which is also y = (3x)/4

using pythagoras (4^2) = (x^2) + (y^2)
(4^2) = (x^2) + (3x/4)^2)
16 = (x^2) + (9(x^2)/16)
16 = (x^2) + (9(x^2)/16)
256 = 16(x^2) + 9(x^2)
256 = 25(x^2)
(x^2) = 10.24

x = 3.2

if x = 3.2, then y = 2.4...

gradient of orginal line = 3/4

y-y1=m(x-x1)
y - 2.4 = (-4/3)(x - 3.2)
y - 2.4 = -4x/3 + 64/15
y - 20/3 + 4x/3 = 0
3y + 4x - 20 = 0

we know the y coordinate of the centre to be 4. if y=4 then...

12 + 4x - 20 = 0
4x = 8
x = 2

if the centre of the circle has x = 2, and the circumference is at o then the radius, r, = 2
4. (Original post by Aitch)
I get r = 2.

I think I need a diagram.

Aitch
i had r=2, went to post, got logged out, lost solution, did it again, and got r = 2 again... without diagram...
5. (Original post by El Stevo)
i had r=2, went to post, got logged out, lost solution, did it again, and got r = 2 again... without diagram...
6. (Original post by El Stevo)
i had r=2, went to post, got logged out, lost solution, did it again, and got r = 2 again... without diagram...
I won't bother with the diagram now!

I worked with the 2 triangles with smallest angle = arctan 3/4
Then a perpendicular dropped from the centre meets 4y=3x at 5r/4 below the centre.
at that point the y coord is 3/4 *r

so 2r =4 (between centre and x-axis)

Aitch
7. Don't say you're 'not near AEA standard'. AEA exams are supposed to be difficult and thus you're not expected to get every question right.
8. when is the AEA exam taken? end of AS?
9. (Original post by C4>O7)
when is the AEA exam taken? end of AS?
After you finish your A level course.
10. Hey THAT WAS THE PAPER I DID!!!

Q1.. I left it... but aparently my mate said it was easy... mind you... BE VERY CAREFUL AT THE END.. x=0 DOES NOT SATISFY

Q2... easy...

Q3... easy...

Q4...for the circle... equate the parametric equation of the circle with the cartesian of the line I remember... to get the point of intersection...

Q5... it was ok...

Q6 ok...

Q7... RUN OUT OF TIME...
11. Found my (pretty ropey) diagram!

Two 3/2,4/2,5/2 triangles.

a hypotenuse and a shortest side = 4 = 2r !

Aitch
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