Please someone help, im so confused

This question is about a 5.0μF capacitor which is charged with a 20V supply. It is then discharged through a 10kΩ resistor.

Part B
Voltage after two time constants
Calculate the voltage across the capacitor two time constants after the discharging starts.

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Nitrotoluene

Original post

by LisaPerera

This question is about a 5.0μF capacitor which is charged with a 20V supply. It is then discharged through a 10kΩ resistor.
Part B
Voltage after two time constants
Calculate the voltage across the capacitor two time constants after the discharging starts.

Discharge of a capacitor
Data: C = 5.0 μF, V° = 20 V, R = 10 kΩ
Time constant: τ = R × C = 50 ms
Voltage after 2τ:
The voltage during discharge follows the law: V(t) = V° × e^(-t/τ)
After two time constants:
V(2τ) = 20 V × e^-2 = 2.7 V, which represents approximately 13.5% of the initial voltage.

Ciao,
Sandro