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E = mc2 [closed - user ignored questions about the purpose of the thread]

In "Relativity: Special and General Theory" (1917), Einstein's inertial mass (Eo/c2) is used to form E = mc2.


"IT is clear from our previous considerations that the (special) theory of relativity has grown out of electrodynamics and optics." (Einstein4, § 15).


"Hence we can say: If a body takes up an amount of energy Eo, then its inertial mass increases by an amount Eo/c2 " (Einstein4, § 15).



The absorption of a photon by a body does not increase the mass (Eo/c2) of an object; consequently, the increase in the mass (Eo/c2) of the object is zero (m = 0). In addition, Einstein’s photon energy equation E = mc2 is used to justify the quantization of Maxwell’s electromagnetic fields where a discrete photon’s energy (E) is absorbed by a body but the mass of a propagating or a photon at rest is zero (m = 0). Plus, Maxwell's electromagnetic fields are based on Faraday's induction effect that does not involve the emission of light; consequently, Einstein's energy equation E = mc2 is an analogy since a magnet cannot oscillate at the frequency of light which invalidates E = mc2.


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Me: For a photon is E = mc2 invalid? (less than ten words).


As ChatGPT: Yes for a photon, E=mc2 is not valid, because a photon has zero rest mass (m=0).
(edited 3 weeks ago)
I think you are finding that copy & pasting random content from elsewhere and repeatedly editing your first posts does not encourage a discussion.
Original post
by carleto1234
Newton's gravity equation is applied to an astronaut (50 kg) in the spacecraft hovering 249 miles over a fix point above the surface of the Earth. The distance from the center of the Earth to the hovering spaceship is calculated,


r = (earth's radius) + (height) = (6.371 x 106 m) + (.4 x 106 m) = 6.771 x 106 m..........................................................103



Equation 72 is used to form the gravitational force on the astronaut using Newton's gravity equation (equ 71),



F = (G m1 m2)/r2 = (6.7 × 10-11) x (50kg) x (6 x 1024kg) / (6.771 x 106m)2 438.4 N or 44.7 kg ...................................104



A 50 kg astronaut in the spaceship forms a 44.7 kg gravitational force yet the astronaut is weightless which invalidates the sling shot that is based on Newton's gravity equations. It is argued that the weightlessness of the astronaut is caused by the free fall of the spaceship towards the Earth but the spaceship that is propagating towards the Moon is not falling to the Earth yet the astronaut in the CMSL are weightless during the voyage to the Moon. The rotational inertia is used to justify the weightlessness of the astronaut but if the astronaut in a jetpack is accelerated in the opposite direction tangent to the assumed orbital path, the astronaut in the jetpack would not experience a downward force. According to NASA, the astronauts are free falling in the same direction as their spacecraft. When the Apollo 11 spacecraft is on its way to the Moon, it is moving along a curved trajectory around Earth. The spacecraft and everything inside it, including the astronauts, are accelerating under gravity at the same rate. Because the astronauts and the spacecraft are accelerating together, there is no contact force between the astronauts and the floor of the spacecraft, so they feel weightless. The direction of free fall is toward the Earth but since the spacecraft is moving tangentially at high speed, the astronauts don’t actually fall straight down, they follow the same orbital path as the spacecraft. The astronauts are free falling in the direction of Earth’s gravity, along the orbital path of the spacecraft, which is why they float inside the cabin. Their free fall is toward Earth but because the spacecraft has high tangential velocity, they follow the curved trajectory of the spacecraft instead of falling straight down, which is why they experience weightlessness. The CSML that is propagating towards the Moon cannot be falling towards the Earth in the ostensible free fall explanation which proves the free fall, that is essential to the Apollo 11 mission, is physically invalid.

Hello, thank you for posting in chemistry study help.:smile:
To help others to answer your question, would you be able to give a 2 sentence explanation for what advice you are looking for?

Thanks,
MR
Sadly two replies doth not a discussion make. Toodle-pip old bean.
Original post
by carleto1234
Do you love and admire me? Since valentine day is soon to come, if the chemistry is right that is.
❣️💞💘


No.
Can you answer my question so that I can make sure your discussion is in the right place and stays open?

Reply 5

Me: For a photon is E = mc2 invalid? (less than 10 words include E = mc2).

As ChatGPT: Yes for a photon, E=mc2 is not valid, because a photon has zero rest mass (m=0).

Gemini said: Correct. Photons have zero mass, making E=mc2 invalid.

Google Search: Yes, E=mc^2 is invalid as photons lack mass.

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