Vector Triangle

    • Thread Starter

    I have attached a question about vector triangles and how i would work it out. Cant think of a way forward apart from sine rule
    Any mistakes in drawing the triangle? Just wanting you guys to check
    Attached Images

    {T1}sin(40) + {T2}sin(60) = 35g

    {T1}cos(40) = {T2}cos(60)
    • Thread Starter

    (Original post by DeanK2)
    {T1}sin(40) + {T2}sin(60) = 35g

    {T1}cos(40) = {T2}cos(60)
    Hey, i thought of doing it that way
    but how come T1cos40 = T2cos60 ??
    I know that the sum should be equal to 35g, tried that way but couldnt progress further

    EDIT: got it, horizontally should also be equal because in equilibrium, thanks for your help

    EDIT AGAIN : Then also, i still dont get it would you get 2 relations then solve?
    • Thread Starter


    You can use the sine rule to find T1 and T2

     \frac{T1}{sin50} =  \frac{35g}{sin100}

     T1 = \frac{35gsin50}{sin100}

    Then repeat for T2.
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