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ionic half equation watch

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    hi, cud sum1 plz help me with these questions.

    Br2(l) + S2O3 (2-) + H20(l) = 3H+ + Br- + 2SO4 (2-)

    soz, its nt dat clear 2 see but can sum1 tell me wat the half equations of this would be? Oxidation and redution?

    thank u
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    (Original post by urban_flavaz)
    hi, cud sum1 plz help me with these questions.

    Br2(l) + S2O3 (2-) + H20(l) = 3H+ + Br- + 2SO4 (2-)

    soz, its nt dat clear 2 see but can sum1 tell me wat the half equations of this would be? Oxidation and redution?

    thank u
    Write down the half equations

    I think that your problem lies with the fact that when thiosulphate reduces it turns to the tetrathionate ion S4O6(2-)

    Br2 + 2e ---> 2Br-
    2S2O3(2-) ---> S4O6(2-) + 2e

    now that the electrons are balanced the equations can be added
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    He was asking for oxidation and reduction, so, charco, please allow me to add something that might be useful for him.

    (Original post by charco)
    Br2 + 2e ---> 2Br-
    This is reduction. Br is the oxidizing agent.

    (Original post by charco)
    2S2O3(2-) ---> S4O6(2-) + 2e
    This is oxidation. S2O3 is the reducing agent.

    (Original post by charco)
    when thiosulphate reduces it turns to the tetrathionate ion S4O6(2-)
    The whole thing is a redox equation.
 
 
 

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