This discussion is now closed.
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If (i) is true then y is in a(A). So y is in a(A) u a(B).
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If (ii) is true then y is in a(B). So y is in a(A) u a(B).
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If (i) is true then there is an x in A such that a(x) = y. Since x is in A u B, y is in a(A u B).
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If (ii) is true then there is an x in B such that a(x) = y. Since x is in A u B, y is in a(A u B).
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