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Maths Challenge watch

    • Thread Starter

    ok, for this question, there are 14 variables, A,B,C,D,E,F,G,H,I,L,M,N,O,P

    All letters are added up NOT MULTIPLIED, eg if V = 2, then in the eqn VT=5 , T would equal 3

    The equations are as follows;

    BANDAGE = 59

    POMMEL = 71

    GLIDE = 58

    HAGGLE = 59

    CAPPED = 108

    BOC = 47

    HILD = 72

    NOM = 20

    all values above 0

    Whoever solves all 14 unknowns will receive 100 rep! (10 days of rep!)

    Hmmm, eight equations in fourteen unknowns.

    Think that just about excludes it from "", the set of solvable problems!

    ..it means that it is not restricted to one solution. eg. 2x+y=3, (x,y>0): The only integer solution is x=1,y=1, but there exists an infinite number of non-integer solutions.
    It may be the case that this problem has only one possible all-integer solution- it will just require some lucky guesses to solve.

    (Original post by flyinghorse)
    Hmmm, eight equations in fourteen unknowns.

    Think that just about excludes it from "", the set of solvable problems!
    Like a matrice 8x14 ... with another condition all the values are greater than 0 (I think they should be integers as well) lol. Use the computer to do it
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Updated: March 2, 2005

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