The Student Room Group
Reply 1
The first part is it 2 . [ sqrt 3/4]
or 2 . [(sqrt 3)/4]
??
Also what do you want done, just simplifying?
Reply 2
Oh sorry, forgot to mention that it's to be manipulated into finding x ~

It's 2 . [ (sqrt 3 )/4) ] etc. etc.
Reply 3
well i get this:

2 . [(sqrt 3)/4 . (4/sqrt 3x)^2 = 3 . ( 4 / square root of 3x ) x
2 . [4/sqrt 3x] + 3 . [4/sqrt 3x] x
[4/sqrt 3x](2 +3x)
[4(2 + 3x)(sqrt 3)]/3x

Umm I dont know what you want from here. I think this is what you were asking for. I may be mistaken.

Latest