Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Oh, Probablility...

Given P(A)=.6, P(A

\land

B')=.4, and P(A

\lor

B)=.85, Find the value of P(B).

I started by filling what was given into some formulae...

.85= .6 + P(B) - P(A

\lor

B)
.4= .6+ P(B') - P(A

\lor

B')

Am I on the right track?

B or P(B)?

OP

Kevin_B

B or P(B)?

yeah, P(B), my mistake, I just edited.

P( A and B' ) is just the intersection of A without B, draw a venn diagram and you can find the intersection, then use P( A or B ) = P(A) + P(B) - P( A and B ). Is this edexcel?

nk9230

Given P(A)=.6, P(A

\land

B')=.4, and P(A

\lor

B)=.85, Find the value of P(B).

I started by filling what was given into some formulae...

.85= .6 + P(B) - P(A

\lor

B)
.4= .6+ P(B') - P(A

\lor

B')

Am I on the right track?

First equation should be:

.85= .6 + P(B) - P(A \land B)

For your second equation I would look to express the probability of A in terms of the two subsets

A\land B\text{ and }A\land B'

OP

Kevin_B

P( A and B' ) is just the intersection of A without B, draw a venn diagram and you can find the intersection, then use P( A or B ) = P(A) + P(B) - P( A and B ). Is this edexcel?

No, IB Maths SL.

OP

ghostwalker

First equation should be:

.85= .6 + P(B) - P(A \land B)

For your second equation I would look to express the probability of A in terms of the two subsets

A\land B\text{ and }A\land B'

Yeah, I typed the equation in wrong :p:

:p:

, and How would I do that?

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