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Maths P1 Question, Help!!!
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#1
The sixth term of an arithmetic sequence is equal to twice the the fourth term, and the tenth term equals 48. find the first term "a" and the common difference "d":
here goes:
6th term = 2 * (4th term)
4th term = a + 3d
6th term = 2 (a + 3d)
so, 6th term = 2a + 6d
10th term = a + 9d = 48
help!! i got to this part. i was thinking to simultaneously solve the 2 equations to find "a" and "d", but i dont have an actual value for the 6th term. i only know that the 10 term is 48. please help someone!!
here goes:
6th term = 2 * (4th term)
4th term = a + 3d
6th term = 2 (a + 3d)
so, 6th term = 2a + 6d
10th term = a + 9d = 48
help!! i got to this part. i was thinking to simultaneously solve the 2 equations to find "a" and "d", but i dont have an actual value for the 6th term. i only know that the 10 term is 48. please help someone!!
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#2
(Original post by Meander)
The sixth term of an arithmetic sequence is equal to twice the the fourth term, and the tenth term equals 48. find the first term "a" and the common difference "d":
here goes:
6th term = 2 * (4th term)
4th term = a + 3d
6th term = 2 (a + 3d)
so, 6th term = 2a + 6d
10th term = a + 9d = 48
help!! i got to this part. i was thinking to simultaneously solve the 2 equations to find "a" and "d", but i dont have an actual value for the 6th term. i only know that the 10 term is 48. please help someone!!
The sixth term of an arithmetic sequence is equal to twice the the fourth term, and the tenth term equals 48. find the first term "a" and the common difference "d":
here goes:
6th term = 2 * (4th term)
4th term = a + 3d
6th term = 2 (a + 3d)
so, 6th term = 2a + 6d
10th term = a + 9d = 48
help!! i got to this part. i was thinking to simultaneously solve the 2 equations to find "a" and "d", but i dont have an actual value for the 6th term. i only know that the 10 term is 48. please help someone!!
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#3
lol..........ohh my god i am so thick. how on earth did i make such a mistake. well, i am really stuck now, please can someone help!!!
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#6
(Original post by Meander)
lol..........ohh my god i am so thick. how on earth did i make such a mistake. well, i am really stuck now, please can someone help!!!
lol..........ohh my god i am so thick. how on earth did i make such a mistake. well, i am really stuck now, please can someone help!!!
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#8
(Original post by theone)
a+5d = 2a + 6d. So a+d = 0.
a+5d = 2a + 6d. So a+d = 0.
That right theone?
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#9
I don't know if this is right, if it is, I am Jesus
a+3d = 2a+6d
0=a+3d
48=a+9d
6d=48 d =8
a+ 9(8) = 48
a+72 = 48
a=48-72 = -24
test - a+3d =2a + 6d
-24 + 24 = -48 + 48
0 = 0 its correctamundo
a+3d = 2a+6d
0=a+3d
48=a+9d
6d=48 d =8
a+ 9(8) = 48
a+72 = 48
a=48-72 = -24
test - a+3d =2a + 6d
-24 + 24 = -48 + 48
0 = 0 its correctamundo
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#10
(Original post by gayboy09)
I don't know if this is right, if it is, I am Jesus
a+3d = 2a+6d
0=a+3d
48=a+9d
6d=48 d =8
a+ 9(8) = 48
a+72 = 48
a=48-72 = -24
test - a+3d =2a + 6d
-24 + 24 = -48 + 48
0 = 0 its correctamundo
I don't know if this is right, if it is, I am Jesus
a+3d = 2a+6d
0=a+3d
48=a+9d
6d=48 d =8
a+ 9(8) = 48
a+72 = 48
a=48-72 = -24
test - a+3d =2a + 6d
-24 + 24 = -48 + 48
0 = 0 its correctamundo
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#11
On this instant you should ignore gayboy09, his maths is as rusty as a nail that is rusty.
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#12
(Original post by gayboy09)
On this instant you should ignore gayboy09, his maths is as rusty as a nail that is rusty.
On this instant you should ignore gayboy09, his maths is as rusty as a nail that is rusty.
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#13
ahhh, i see it. we find two expressions for the 4th and 6 th term, we then cancel this to give us an equation. we tthen use this equation and solve it simultaneoulsy with: 10 term = a + 9d = 48 to find a and d:
a + d = 0
a + 9d = 48
-8d = 48
d = 48/(-8)
d = -6
sub d=-6 back into a+d = 0:
a + (-6) = 0
so a = 6
therefore the first term ("a") = 6
the common difference = -6
hooray!!!!!!!
a + d = 0
a + 9d = 48
-8d = 48
d = 48/(-8)
d = -6
sub d=-6 back into a+d = 0:
a + (-6) = 0
so a = 6
therefore the first term ("a") = 6
the common difference = -6
hooray!!!!!!!
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#14
where on earth did you guys get d = 8 from? you are using the wrong equation, you are using a + d =0. where did this 3d come from? i got the right answer coz my answer sheet says so. you did it wrong some of you guys
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#15
(Original post by meander)
ahhh, i see it. we find two expressions for the 4th and 6 th term, we then cancel this to give us an equation. we tthen use this equation and solve it simultaneoulsy with: 10 term = a + 9d = 48 to find a and d:
a + d = 0
a + 9d = 48
-8d = 48
d = 48/(-8)
d = -6
sub d=-6 back into a+d = 0:
a + (-6) = 0
so a = 6
therefore the first term ("a") = 6
the common difference = -6
hooray!!!!!!!
ahhh, i see it. we find two expressions for the 4th and 6 th term, we then cancel this to give us an equation. we tthen use this equation and solve it simultaneoulsy with: 10 term = a + 9d = 48 to find a and d:
a + d = 0
a + 9d = 48
-8d = 48
d = 48/(-8)
d = -6
sub d=-6 back into a+d = 0:
a + (-6) = 0
so a = 6
therefore the first term ("a") = 6
the common difference = -6
hooray!!!!!!!
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#16
lol, oops tes, i was rushing a bit there. when i did the question on paper i did it correctly as you said...........i just typed it too fast...
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#17
(Original post by Meander)
lol, oops tes, i was rushing a bit there. when i did the question on paper i did it correctly as you said...........i just typed it too fast...
lol, oops tes, i was rushing a bit there. when i did the question on paper i did it correctly as you said...........i just typed it too fast...
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#19
(Original post by Bhaal85)
I would answer, but I'm off to bed. Night all.
I would answer, but I'm off to bed. Night all.
Oh well I'm off too. See y'all tomorrow!
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