The Student Room Group
Reply 1
Circular motion and gravitation equations.

Centripetal force of the circular motion is provided by earth's gravity.
Reply 2
Really big weighing scales, to get the weight. Then convert that into mass :biggrin:
Reply 3
I bet Google would know :smile:
Reply 4
g=Gm/r^2

you need the radius and the gravitational field on the moon and G=6.67x10^-11 m^2 kg^-2 this G is the universal gravitational constant.

radius of the moon = 1 737.4 x10^3 m

g=1.6 N kg^-1 on the moon

m=g x r^2/G

= 7.24x10^22 kg, the reason why it's slightly less here because of the roudning up with G and g.
Reply 5
fL3X
g=Gm/r^2

you need the radius and the gravitational field on the moon and G=6.67x10^-11 m^2 kg^-2 this G is the universal gravitational constant.

radius of the moon = 1 737.4 x10^3 m

g=1.6 N kg^-1 on the moon

m=g x r^2/G

= 7.24x10^22 kg, the reason why it's slightly less here because of the roudning up with G and g.



Thanks a billion, finally got it. I spent like two hours using these equations but i ended up using g=9.81 and not 1.6. Cheers.
Reply 6
g=1.6 N kg^-1 on the moon << How determined?
Reply 7
How determined g on the moon?
The value of "g" on the Moon is calculated from a knowledge of the mass of the Moon; not the other way round.
The mass of the Moon is calculated nowadays from observation of the motion of lunar orbiters. The first such accurate calculations were made in the 60s.
(edited 11 years ago)