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#1
A charge of 25C is moved through an electric field of 6000V in 3 minutes. HOw much power does the electric field use in moving the charge? plz help
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#2
(Original post by Kleverkirsty)
A charge of 25C is moved through an electric field of 6000V in 3 minutes. HOw much power does the electric field use in moving the charge? plz help
A charge of 25C is moved through an electric field of 6000V in 3 minutes. HOw much power does the electric field use in moving the charge? plz help
I=Q/t
I=25/(3*60)=0.138...
P=IV
P=0.138...*6000=833.33... = 830 Watts (2 sf)
i think thats it
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#3
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
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#4
(Original post by Unregistered)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)

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#5
(Original post by Unregistered)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
0
Report
#6
(Original post by Unregistered)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
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