# Electricity

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18 years ago
#1
A charge of 25C is moved through an electric field of 6000V in 3 minutes. HOw much power does the electric field use in moving the charge? plz help
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18 years ago
#2
(Original post by Kleverkirsty)
A charge of 25C is moved through an electric field of 6000V in 3 minutes. HOw much power does the electric field use in moving the charge? plz help
Q=It
I=Q/t
I=25/(3*60)=0.138...

P=IV
P=0.138...*6000=833.33... = 830 Watts (2 sf)

i think thats it
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18 years ago
#3
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
0
18 years ago
#4
(Original post by Unregistered)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf) 0
18 years ago
#5
(Original post by Unregistered)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
I think you'll find that Q=25 as in the question. Nice try.
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18 years ago
#6
(Original post by Unregistered)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
Where did the I = 20 come from? It's I = 25.
0
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