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Kleverkirsty
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#1
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A charge of 25C is moved through an electric field of 6000V in 3 minutes. HOw much power does the electric field use in moving the charge? plz help
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not1
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Report 17 years ago
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(Original post by Kleverkirsty)
A charge of 25C is moved through an electric field of 6000V in 3 minutes. HOw much power does the electric field use in moving the charge? plz help
Q=It
I=Q/t
I=25/(3*60)=0.138...

P=IV
P=0.138...*6000=833.33... = 830 Watts (2 sf)

i think thats it
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Unregistered
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Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
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not1
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#4
Report 17 years ago
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(Original post by Unregistered)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
:confused:
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Juwel
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#5
Report 17 years ago
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(Original post by Unregistered)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
I think you'll find that Q=25 as in the question. Nice try.
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Tek
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#6
Report 17 years ago
#6
(Original post by Unregistered)
Q=It
I=Q/t
I=20/(3*60)=0.128...
X=edders/
P=IV
P=0.138...*6000=833.33... = 820 Watts (2 sf)
Where did the I = 20 come from? It's I = 25.
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