The Student Room Group

Very easy mechanics question

It is part (iii) which has stumped me but I thought I would give you the prologue aswell.

A load of mass 150kg is accelerating vertically upwards as the result of the pull of a crane wire. tension in the wire is 1488N
(i) Assuming only forces are weight and tension calculate acceleration.
(ii) measurements actually show a = 0.05ms-2 because of resistance to motion of the load, calculate the resistance.

(iii) In a new situation the load is accelerating downwards at 4ms-2 and resistances to the motion or negligible
Show that the tension in the crane wire is 870N


All of this is based round simple F=ma stuff, netwon's second law as it were, but this really has me stumped :frown: and made me feel quite stupid.

any help would be appreciated.
A_Fictitious
(iii) In a new situation the load is accelerating downwards at 4ms-2 and resistances to the motion or negligible
Show that the tension in the crane wire is 870N


All of this is based round simple F=ma stuff, netwon's second law as it were, but this really has me stumped :frown: and made me feel quite stupid.

any help would be appreciated.


What forces are acting on the object?
Reply 2
Make sure that you remember to include gravity in this. Because the load is moving downwards with an acceleration of less than
Unparseable latex formula:

9.8\ \mbox{ms}^{-2}

, the crane wire is preventing it from freefalling. You could just set up an FR=maF-R=ma equation. Using downwards as the positive direction, that gives you WT=4mW - T = 4m (where m is the mass, W is the weight and T is the tension).
Reply 3
ahh yes thank you nuodai, I was almost there.
Original post by A_Fictitious
ahh yes thank you nuodai, I was almost there.

Did you do part 4?

Spoiler