#1
So our class has just started a new chapter.

And Ive been stuck on this question for like an hour now its really annoying me.

A minor arc AB of a circle, Centre O and radius 10cm subtends an angle x at O. The major arc AB subtends an angle 5x at O. Find in terms of (Pie), the length of the minor arc AB.

I know the answer but I don't know the method to get to it.

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9 years ago
#2
(Original post by Jamezzy)
So our class has just started a new chapter.

And Ive been stuck on this question for like an hour now its really annoying me.

A minor arc AB of a circle, Centre O and radius 10cm subtends an angle x at O. The major arc AB subtends an angle 5x at O. Find in terms of (Pie), the length of the minor arc AB.

I know the answer but I don't know the method to get to it.

total circle angle is 6x.
Therefore, considering 360 degrees is two pi, the answer would be 1/6(2 pi) x 10

(as the arc length is the degree multiplied by the radius)
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#3
(Original post by Danielisew)
total circle angle is 6x.
Therefore, considering 360 degrees is two pi, the answer would be 1/6(2 pi) x 10

(as the arc length is the degree multiplied by the radius)
Thanks but the answer in the book says 10pi/3 cm.

I was wondering how to get to that from 1/6(2pi) x 10.
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9 years ago
#4
(Original post by Jamezzy)
Thanks but the answer in the book says 10pi/3 cm.

I was wondering how to get to that from 1/6(2pi) x 10.
1/6 2 pi x 10

(multiply by 2, which makes the 1/6 into 1/3)

= 1/3 pi x 10

(simplify)

= 10pi/3

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9 years ago
#5
(Original post by Jamezzy)
So our class has just started a new chapter.

And Ive been stuck on this question for like an hour now its really annoying me.

A minor arc AB of a circle, Centre O and radius 10cm subtends an angle x at O. The major arc AB subtends an angle 5x at O. Find in terms of (Pie), the length of the minor arc AB.

I know the answer but I don't know the method to get to it.

It is obvious that angle radians.

If you know what 6x is in pi radians, you can find x. Then you use the formula, , where s is the length of the minor arc.
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9 years ago
#6
I just literally done this question and came on here for some help for 6B. q. 10 lol
anyway heres what i got:
x = 1/6 x 2pi = 2/6 pi
L = 10 x 2/6 pi
L = 20/6 pi
L = 10/3 pi
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#7
(Original post by jimber)
I just literally done this question and came on here for some help for 6B. q. 10 lol
anyway heres what i got:
x = 1/6 x 2pi = 2/6 pi
L = 10 x 2/6 pi
L = 20/6 pi
L = 10/3 pi
lol thanks
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