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    • Thread Starter

    Could you please help me?

    'A fairground game involves trying to hit a moving target with a gunshot. A round consists of up to 3 shots. 10 points are scored if a player hits the target, but the round is over if the player misses. Linda has a constant probability 0.6 of hitting the target and shots are independent of one another.'

    A game consists of 2 rounds. Find the probability that Linda scores more points in round 2, than in round 1.

    I'm really stuck on this question. I've started by listing all the possible scores in Round 2, which are:

    10 + 10 + 10
    10 + 10 + 0
    10 + 0 + 0

    The bit that is really confusing me, is the more points that round 1 bit. Could someone give me some pointers?

    You could also get 0+0+0 (I know this won't beat Round 1 but it could still happen)
    First work out the probabilities of getting each score.
    • Thread Starter

    (Original post by MathsHamster)
    You could also get 0+0+0 (I know this won't beat Round 1 but it could still happen)
    First work out the probabilities of getting each score.
    Ok, so I've got

    10 + 10 + 10 = 0.216
    10 + 10 + 0 = 0.36
    10 + 0 = 0.24 (due to the fact, the round ends when you miss so 0.6 x 0.4)

    So do I times the probability of getting 10 in one round, and then 20 in next together, get as many combinations as possible and add them together?

    This is a question from the November session...Take a look at the mark scheme...Its given pretty clearly over thr...

    You can use a tree diagram, tht will be helpful!
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Updated: March 19, 2009

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