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# Need help with maths quick . due in on friday watch

1. s h o w usi ng th eor ems of ca lc ulus th at the p o l y n o m i a l

p( x) = x ^5 + 2x ^3 - 5 x + 1 h a s a t le as t th r ee ro o t s

(had to put random spaces so that. the lecuturer wouldnt be able to google and find out i cheated)
2. (Original post by help me)
s h o w usi ng th eor ems of ca lc ulus th at the p o l y n o m i a l

p( x) = x ^5 + 2x ^3 - 5 x + 1 h a s a t le as t th r ee ro o t s

(had to put random spaces so that. the lecuturer wouldnt be able to google and find out i cheated)
Gosh, you're paranoid aren't you.
Gosh, you're paranoid aren't you.
need to be. its an assesed coursework. and if there is any hint of plagarism. i get null marks
4. (Original post by hel me)
need to be. its an assesed coursework. and if there is any hint of plagarism. i get null marks
Well, then maybe you should be good and do it the proper way.
Well, then maybe you should be good and do it the proper way.
i wouldnt be here . i f i could.
6. do you mean p(x)=0 has 3 roots?
7. (Original post by It'sPhil...)
do you mean p(x)=0 has 3 roots?
sh ow ta hat p9x has a t llleaaaaaast 3 rooots
8. come on someone. need bad
9. (Original post by hlpgs)
why does the name keep changing!??????
10. (Original post by Saf!)
why does the name keep changing!??????
there
11. (Original post by cos i cant type)
there
come on pls
12. Well you can't expect someone to just do it for you!

But bear this in mind, you want to find where the polynomial equals zero, so imagine the graph of p(x) against x - what happens when p(x) equals zero? Also remember that a particular part of calculus (it's not that hard to figure out which) can eventually lead to finding turning points of the graph. That's about as much help I think a reasonable maths teacher would give, good luck!
13. (Original post by help me)
s h o w usi ng th eor ems of ca lc ulus th at the p o l y n o m i a l

p( x) = x ^5 + 2x ^3 - 5 x + 1 h a s a t le as t th r ee ro o t s

(had to put random spaces so that. the lecuturer wouldnt be able to google and find out i cheated)
This is really straightforward - just consider f(-10), f(0), f(1) and f(10).
14. (Original post by theone)
This is really straightforward - just consider f(-10), f(0), f(1) and f(10).
Admittedly that is the most straightforward way, but apparently calculus has to be used, ergo I think they're expected to do the old 'if a graph turns blah blah blah it must cross the axis' [/not even intended to be word for word accuracy )

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