The Student Room Group

Please,solve this maths question for me.

A bag contains 3 black beads, 5 red beads and 2 green beads.
Gianna takes a bead at random from the bag, records its colour and replaces it.
She does this two more times.
Work out the probability that, of the three beads Gianna takes, exactly two are the same colour


Well the answer is 33/50. It is from past paper.But some statistical stuff was used here, which is kinda irrelevant in separate maths paper. My teacher taught us drawing this probability tree, but still after trying it i didnt get a right answer. Please help.The question worths 5 marks and i from higher past paper
Reply 1
did u get the wrong answer as 11/45??
Reply 2
Okay it's been a while since I did probability, but I made a method up and it seemed to come out with the right answer :smile: If I could remember, I think you may need to use Pascals triangle, but whatever.

Black 3/10
Red 5/10
Green 2/10

1st 2nd 3rd 1stx2ndx3rd Total sum
3 3 2 18 54 (this is 18 x 3)
3 2 3
2 3 3

2 2 3 12 36 (12 x 3 etc)
2 3 2
3 2 3

5 2 2 20 60
2 5 2
2 2 5

5 5 3 75 225
5 3 5
3 5 5

5 3 3 45 135
3 3 5
3 5 3

2 5 5 50 150
5 2 5
5 5 2
Total 660/1000
Simplified 330/500 = 33/50


I found all the possible combinations of numbers and in this case, the order does matter.
Reply 3
IZZY!
A bag contains 3 black beads, 5 red beads and 2 green beads.
Gianna takes a bead at random from the bag, records its colour and replaces it.
She does this two more times.
Work out the probability that, of the three beads Gianna takes, exactly two are the same colour


Well the answer is 33/50. It is from past paper.But some statistical stuff was used here, which is kinda irrelevant in separate maths paper. My teacher taught us drawing this probability tree, but still after trying it i didnt get a right answer. Please help.The question worths 5 marks and i from higher past paper


lol, when i first saw this, i thought what a horrible question it was. if you were to add up all the combinations you want to find, you'd need to prcess 18 of the 27 possibilities - not a nice job. instead, i realised it would be quicker to take away the other possibilities. so we are left with:

p(2 same colour) = 1 - p(all red, green or black) - p(one of each colour)

= 1 - (3/10)^3 - (5/10)^3 - (2/10)^3 - 6(3/10 x 5/10 x 2/10)

= 0.66

hurrah.
Reply 4
thank you.