truck Z truck Y truck X Engine
100N<---------- 100N<---------- 300N<---------500N<---------->37000N
........ l 20000kg l ----- l 20000kg l ----- l40000kg l --------l 40000kg l
........ ---------- .........-----------.......--------- .......... -----------
A train consists of an engine and three trucks with the masses and resistance to motion as shown in the diagram (best that I could do on here...) There is also a driving force of 37000N. All the couplings are light, rigid and horizontal.
i) show the acceleration of the train is 0.3ms^-2.
ii)Draw a diagra showing all the forces acting on the truck Z inthe line of its motion. Calculate the force in the coupling between trucks Y and Z.
With the driving force removed, brakes applied, so adding a further resistance of 1100N to the totl of the resistances shown in the diagram.
iii)calculate the new acceleration of the train.
iv) calculate the new force in the coupling between trucks Y and Z if the brakes are applied
(A) to the engine
(B) to truck Z
In each case state whether the force is a tension or a thrust.
I have tried all of the questions apart from iv) which I cant work out which equation to use for.
my answers are
i) i got 0.225ms^2 not 0.3ms^2 i did total force(27000) / total mass (120000)
ii) I got the total to be 392000N
iii) 0.1s^-2
any help on the last question would be very helpful indeed, and if possible and corrections on my previous answers...
Thanks