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C1 question.

Hey,

I'm stuck on some C1 questions from Edexcel, i am revising C1 and have forgotten how to do this. The questions are from the new C1 textbook:

Ex 5C, questions 6 and 7.

(6) The lines

y = x

and

y = 2x-5

intersect at the point A. Find the equation of the line with gradient is

\frac{2}{5}

that passes through point A. (Hint: Solve equations simultaneously).

(7) The lines

y = 4x-10

and

y = x-1

intersect at the point T. Find the equation of the line with gradient -

\frac{2}{3}

that passes through point T. Write your answer in form ax + by +c = 0, where a, b and c are integers.

I understand the concept of what you need to be doing, where you sub in y as 0 and find x and use y - y1 = m(x - x1) in order so find an equation with the given gradient, since that's what that part of the chapter is about. However when I do the simultaneous equations, i get the answer wrong.

Please help.

Reply 1

15

Post your working then. The simultaneous equations are not hard in these examples, so you're probably just making an algebra slip up somewhere.

Reply 2

OP

for (6) I did:

y = 2x - 5

x = 2x - 5

x = 5

therefore, A = (5,0)

y - y_1 = m(x - x_1)

y - 0 = \frac{2}{5} (x - 5)

y = \frac{2}{5}x - \frac{10}{5}

however the answer is

y = \frac{2}{5} + 3

and for (7)

4x - 10 = x-1

4x - 9 = x

3x = 9

x = 3

y - y_1 = m(x - x_1)

y - 0 = -\frac{2}{3} (x - 3)

y = -\frac{2}{3}x + \frac{6}{3}

3y = -2x + 6

2x + 3y - 6 = 0

however the right answer is

2x + 3y - 12 = 0

Reply 3

18

how is the point A (5,0) when it is on the line y=x :/

Reply 4

17

fahadalhasan

for (6) I did:

y = 2x - 5

x = 2x - 5

x = 5

therefore, A = (5,0)

The bit in red is incorrect. What makes you think the y co-ordinate is zero?

Reply 5

if x=5 then put that into y=x and y=5 too
so:
y-5=2/5(x-5)

so y= 2/5x + 3

:biggrin:

:biggrin:

Reply 6

OP

aaaah thank you xD i knew i made silly mistake somewhere

Reply 7

Eleanamarkantoni

1

Why -12 at the end?

Reply 8

17

Original post by Eleanamarkantoni

Why -12 at the end?

Post your working so far - and as you're new here, welcome to the maths forum.

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