The Student Room Group

Reply 1

Propanal -> sodium propanoate:
i. Reflux the propanal with an oxidising agent, potassium dichromate, to convert it to propanoic acid.
ii. Then add sodium hydroxide to convert the acid to sodium propanoate.

Reply 2

endeavour
Propanal -> sodium propanoate:
i. Reflux the propanal with an oxidising agent, potassium dichromate, to convert it to propanoic acid.
ii. Add sodium hydroxide to convert to sodium propanoate.


Thanks, endeavour- you always end up answering all my question, which I really appreciate.

Any ideas on the polymer part anyone?

Reply 3

This is from a past paper, and (unless mine eyes deceive me) it is without a doubt printed as methyl 2-methylpropenoate.

Reply 4

I'm not sure about the actual answer to the polymer q, but the two molecules making up methyl 2-methylpropenoate would be methanol and 2-methylpropenoic acid (through a condensation reaction where water is ejected).

Reply 5

endeavour
I'm not sure about the actual answer to the polymer q, but the two molecules making up methyl 2-methylpropenoate would be methanol and 2-methylpropenoic acid (through a condensation reaction where water is ejected).


The monomer methyl 2-methylpropenoate has a formula of,
CH2=C(CH3)CO2CH3. Does that help? Would the CH3 group react?

Reply 6

I think it's addition reaction
CH3
|
nCH2=C(CH3)COOCH3 ---> -[-CH2-C-]-
|
COOCH3

Reply 7

BCHL85
I think it's addition reaction
CH3
|
nCH2=C(CH3)COOCH3 ---> -[-CH2-C-]-
|
COOCH3

I agree, it is. :smile:

So it's addition polymerisation (by free radical addition mechanism).

Reply 8

endeavour
I agree, it is. :smile:

So it's addition polymerisation (by free radical addition mechanism).

right... so how is polymerisation in the reaction of -CH2 and -CH3 (on the other side) a free radical addition reaction?

Reply 9

endeavour
I agree, it is. :smile:

So it's addition polymerisation (by free radical addition mechanism).


I get the same answer to :smile:.

Mimo remember to be careful when giving organic reagents, to convert an aldehyde (RCHO) to a carboxylic acid (RCOOH) by oxidation you would reflux with an excess of acidified potassium dichromate(VI).

Reply 10

supreme
I get the same answer to :smile:.

Mimo remember to be careful when giving organic reagents, to convert an aldehyde (RCHO) to a carboxylic acid (RCOOH) by oxidation you would reflux with an excess of acidified potassium dichromate(VI).


right- thanks!

Reply 11

Is this AQA module 3?

Reply 12

MC REN
Is this AQA module 3?


EDEXCEL Unit 5