Determination of the formula of hydrated iron(II) sulphate crystals

FeSO4.xH20
The task is to do a titration and then work out the value of x in front of H20
Could someone tell me how we do this?? My titre was 22.4cm3

Reply 1

Golden Maverick

Sharma

FeSO4.xH20
The task is to do a titration and then work out the value of x in front of H20
Could someone tell me how we do this?? My titre was 22.4cm3

Your titre of what? What experiment did you do?

Reply 2

Pete.S

We did a titration, adding 25cm3 of iron(II) sulphate into a conical flask and then adding 20cm3 of sulphuric acid
We titrated this with 0.0100moldm^-3 potassium permanganate
Repeated three times and took the average to get 22.4cm3

Reply 3

dinesh

With that information you want work out how much FE 2+ you had in the system.
You need to know how much mass of the salt is in the solution.
, and you can find the # of moles of the salt present.
You can now find out the # of moles of the Fes04 with the titre value, find the Mass , and minus it from the intial mass dissolved.
This is the mass of H20 from the salt. Find the # of moles of h20 , and use the ratio of # of moles of Salt : # of moles of H20 and work it out :smile:

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Determination of the formula of hydrated iron(II) sulphate crystals

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