Simple oxidation states

Hey, my text book doesn't have the answers to questions so I was just wondering if you could tell me what the answers for a few so I can check I'm doing it right before moving onto the harder redox equations.

All I have to work out is the oxidation states for each element.

P_4

K_2 Cr_2 O_7

Li Al H_4

P Cl_4 +

OH -

Thanks

Reply 1

danhirons

p = 0
Not sure.
Li = +1, Al = +3, H = -1
P = -3, Cl = +4
O = -2, H = +1

Hope they're right. Not 100% sure though.

Reply 2

EierVonSatan

P4 ... P = 0
K2Cr2O7 ... K = +1, Cr = +6, O = -2
LiAlH4 ... Li = +1, Al = +3, H = -1
PCl4 ... P = +5, Cl = -1
OH- ... O = -2, H = +1

Reply 3

Geek1337

EierVonSatan

P4 ... P = 0
K2Cr2O7 ... K = +1, Cr = +6, O = -2
LiAlH4 ... Li = +1, Al = +3, H = -1
PCl4 ... P = +5, Cl = -1
OH- ... O = -2, H = +1

I got them all right.
I wasn't sure about P4 it this just because it has to be 0 overall?

Reply 4

danhirons

Anything just in its element state is always 0.

Reply 5

EierVonSatan

Simply elements are zero :smile:

C, O2, S8, N2, Ar all zero :yep:

cl is -4 not 4+

Original post by AFAR

cl is -4 not 4+

How do you people even find these threads?

Reply 8

Pigster

Original post by AFAR

cl is -4 not 4+

Agreeing with alow, it is eight year old - leave the dead to rest.

Also, it is -1 (as stated by EierVonSatan) not -4. If you're going to drag up an old thread, read all of it before posting.

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